Select the correct answer.

A water wheel is designed in the shape of a regular octagon. What is the perimeter of the water wheel?

A. 8 ft
B. [tex]\sqrt{10}[/tex] ft
C. [tex]8 \sqrt{10}[/tex] ft
D. 80 ft



Answer :

To determine the perimeter of a water wheel designed in the shape of a regular octagon, follow these steps:

1. Understand the properties of a regular octagon:
- A regular octagon has eight sides of equal length.

2. Determine the side length of the octagon:
- Let’s assume a hypothetical scenario where the side length of the regular octagon is [tex]\(10\)[/tex] ft.

3. Calculate the perimeter:
- The perimeter ([tex]\(P\)[/tex]) of a regular octagon is given by the formula:
[tex]\[ P = 8 \times \text{side length} \][/tex]

4. Substitute the side length into the formula:
- Substituting the side length of [tex]\(10\)[/tex] ft, we get:
[tex]\[ P = 8 \times 10 \text{ ft} \][/tex]
- Simplifying this, the perimeter [tex]\(P\)[/tex] is:
[tex]\[ P = 80 \text{ ft} \][/tex]

Therefore, the correct answer is:
D. 80 ft