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An A-frame restaurant is shaped as a triangle with two side lengths of 20 m and 30 m. Complete the inequality below to describe the range of possible lengths [tex]$x$[/tex] of the third side of the restaurant.

[tex]\square \ \textless \ x \ \textless \ \square[/tex]



Answer :

To determine the range of possible lengths [tex]\( x \)[/tex] for the third side of the A-frame restaurant shaped as a triangle with given side lengths of 20 meters and 30 meters, we can utilize the triangle inequality theorem. This theorem states that the length of one side of a triangle must be less than the sum of the other two sides and greater than the difference of the other two sides.

Given side lengths [tex]\( a = 20 \)[/tex] meters and [tex]\( b = 30 \)[/tex] meters:

1. Calculate the lower bound:
[tex]\[ \text{Lower bound} = \left| 20 - 30 \right| = 10 \, \text{meters} \][/tex]

2. Calculate the upper bound:
[tex]\[ \text{Upper bound} = 20 + 30 = 50 \, \text{meters} \][/tex]

Thus, the length of the third side [tex]\( x \)[/tex] must satisfy the inequality:
[tex]\[ 10 < x < 50 \][/tex]

So, the completed inequality is:
[tex]\[ \boxed{10} < x < \boxed{50} \][/tex]