Answer :

Answer:

Step-by-step explanation:

To find the 36th term in the sequence 20, 16, 12, 8, we need to identify the pattern and determine if it's an arithmetic or geometric sequence    .Given the terms:

given 1st  term 20...... 2nd term 16..... 3rd term 12,,,,,, 4th term 8                            The common difference (

d) can be found by subtracting the first term from the second term:

=

16

20

=

4

d=16−20=−4          he general formula for the

nth term of an arithmetic sequence is:

=

1

+

(

1

)

a

n

=a

1

+(n−1)d    o find the 36th term (

36

a

36

):

36

=

20

+

(

36

1

)

(

4

)

a

36

=20+(36−1)(−4)

36

=

20

+

35

(

4

)

a

36

=20+35(−4)

36

=

20

140

a

36

=20−140

36

=

120

a

36

=−120

Therefore, the 36th term is

120

−120.