What is the value of this expression when [tex]$x = -6$[/tex] and [tex]$y = -\frac{1}{2}$[/tex]?

[tex]4\left(x^2 + 3\right) - 2y[/tex]

A. -131
B. -35
C. [tex][tex]$57 \frac{1}{2}$[/tex][/tex]
D. 157



Answer :

Let's solve the expression step-by-step: [tex]\( 4\left(x^2 + 3\right) - 2y \)[/tex] when [tex]\( x = -6 \)[/tex] and [tex]\( y = -\frac{1}{2} \)[/tex].

1. Calculate [tex]\( x^2 \)[/tex]:
- Given [tex]\( x = -6 \)[/tex]
- [tex]\( x^2 = (-6)^2 = 36 \)[/tex]

2. Substitute [tex]\( x^2 \)[/tex] into the expression [tex]\( x^2 + 3 \)[/tex]:
- [tex]\( x^2 + 3 = 36 + 3 = 39 \)[/tex]

3. Multiply the result by 4:
- [tex]\( 4(x^2 + 3) = 4 \times 39 = 156 \)[/tex]

4. Calculate [tex]\( -2y \)[/tex]:
- Given [tex]\( y = -\frac{1}{2} \)[/tex]
- [tex]\( -2y = -2 \times -\frac{1}{2} = 1 \)[/tex]

5. Combine the results:
- The expression becomes [tex]\( 156 + 1 = 157 \)[/tex]

So, the value of the expression [tex]\( 4\left(x^2 + 3\right) - 2y \)[/tex] when [tex]\( x = -6 \)[/tex] and [tex]\( y = -\frac{1}{2} \)[/tex] is [tex]\( 157 \)[/tex].

Therefore, the correct answer is:
[tex]\[ \boxed{157} \][/tex]

Answer:

D. 157

Step-by-step explanation:

Answer this question using the mathematical process of substitution!

First, rewrite your original equation by replacing x with -6 and y with [tex]-\frac{1}{2}[/tex]:

[tex]4 [(-6)^{2} +3] -2(-\frac{1}{2} )[/tex]

Next, solve following the rules of PEMDAS:

  1. Solve the equation is in the parenthesis: [tex][(-6)^{2} +3][/tex]= 36 +3= 39. The equation is now [tex]4(39) - 2(-\frac{1}{2} )[/tex]
  2. Next, multiply values together: 4×39= 156  ,  -2 ×[tex]-\frac{1}{2}[/tex]= 1. The equation is now 156 + 1.
  3. Add the two values.

Your answer is 157

Learn more about substitution here: https://brainly.com/question/30239658