4. Complete the following story sums.

a. Father brings home [tex]\(5 \frac{3}{8}\)[/tex] chocolates from work. If Mother eats [tex]\(2 \frac{1}{8}\)[/tex], how much is left for me?

b. John buys 3 cakes. He and his friends eat [tex]\(2 \frac{1}{8}\)[/tex]. How much is left over?

c. Sipho has 6 oranges. His family eats [tex]\(2 \frac{1}{6}\)[/tex]. How much is left over?

a. [tex]\(\square\)[/tex]

b. [tex]\(\square\)[/tex]

c. [tex]\(\square\)[/tex]

Reading Fractions:

Bongi enjoys reading. She has read [tex]\(\frac{3}{4}\)[/tex] of a 120-page book. How many pages of the book does she still have to read?



Answer :

Certainly! Let's solve each part of the question step-by-step.

### Part (a):
Question: Father brings home [tex]\( 5 \frac{3}{8} \)[/tex] chocolate from work. If Mother eats [tex]\( 2 \frac{1}{8} \)[/tex], how much is left for me?

Solution:
1. Convert the mixed fractions to improper fractions:
- [tex]\( 5 \frac{3}{8} = 5 + \frac{3}{8} = 5.375 \)[/tex]
- [tex]\( 2 \frac{1}{8} = 2 + \frac{1}{8} = 2.125 \)[/tex]
2. Subtract the chocolate eaten by Mother from the total chocolate brought home:
- [tex]\( 5.375 - 2.125 = 3.25 \)[/tex]

Answer: There is [tex]\( 3.25 \)[/tex] (or [tex]\( 3 \frac{1}{4} \)[/tex]) chocolate left for me.

### Part (b):
Question: John buys 3 cakes. He and his friends eat [tex]\( 2 \frac{1}{8} \)[/tex]. How much is left over?

Solution:
1. Convert the mixed fraction to an improper fraction:
- [tex]\( 2 \frac{1}{8} = 2 + \frac{1}{8} = 2.125 \)[/tex]
2. Subtract the cakes eaten from the total cakes bought:
- [tex]\( 3 - 2.125 = 0.875 \)[/tex]

Answer: There are [tex]\( 0.875 \)[/tex] (or [tex]\( \frac{7}{8} \)[/tex]) cakes left over.

### Part (c):
Question: Sipho has 6 oranges. His family eats [tex]\( 2 \frac{1}{6} \)[/tex]. How much is left over?

Solution:
1. Convert the mixed fraction to an improper fraction:
- [tex]\( 2 \frac{1}{6} = 2 + \frac{1}{6} = 2.16666\ldots \)[/tex] (approximately [tex]\( 2.167 \)[/tex])
2. Subtract the oranges eaten from the total oranges:
- [tex]\( 6 - 2.1666\ldots \approx 3.8333\ldots \)[/tex]

Answer: There are approximately [tex]\( 3.833 \)[/tex] (or [tex]\( 3 \frac{5}{6} \)[/tex]) oranges left over.

### Reading Fractions:
Question: Bongi enjoys reading. She has read [tex]\(\frac{3}{4}\)[/tex] of a 120-page book. How many pages of the book does she still have to read?

Solution:
1. Calculate the total pages Bongi has read:
- [tex]\( \frac{3}{4} \times 120 = 90 \)[/tex] pages
2. Subtract the pages read from the total pages:
- [tex]\( 120 - 90 = 30 \)[/tex]

Answer: Bongi still has 30 pages of the book to read.

So, our answers are:
- (a) [tex]\( 3.25 \)[/tex] pieces of chocolate
- (b) [tex]\( 0.875 \)[/tex] cakes
- (c) [tex]\( 3.833 \)[/tex] oranges
- [tex]\( 30 \)[/tex] pages left to read