To determine how many moles of HCl are present in 250 mL of 1.0 M HCl, we'll proceed as follows:
1. Convert Volume from mL to L:
Given the volume of HCl solution is 250 mL, we need to convert this volume to liters (L) since molarity (M) is defined as moles per liter (mol/L).
[tex]\[
\text{Volume in liters} = \frac{250 \text{ mL}}{1000 \text{ mL/L}} = 0.25 \text{ L}
\][/tex]
2. Identify the Molarity (Concentration) of HCl:
We are given that the molarity of the HCl solution is 1.0 M, which means there are 1.0 moles of HCl in every 1 liter of solution.
3. Calculate the Moles of HCl:
Now we use the relationship between volume, molarity, and moles. The formula to find the number of moles (n) from molarity and volume is:
[tex]\[
\text{moles of HCl} = \text{Molarity (M)} \times \text{Volume (L)}
\][/tex]
Substituting the given values:
[tex]\[
\text{moles of HCl} = 1.0 \text{ M} \times 0.25 \text{ L} = 0.25 \text{ moles}
\][/tex]
Therefore, there are 0.25 moles of HCl present in 250 mL of a 1.0 M HCl solution.
