Which equation represents a line that passes through [tex]\left(4, \frac{1}{3}\right)[/tex] and has a slope of [tex]\frac{3}{4}[/tex]?

A. [tex]y-\frac{3}{4}=\frac{1}{3}(x-4)[/tex]
B. [tex]y-\frac{1}{3}=\frac{3}{4}(x-4)[/tex]
C. [tex]y-\frac{1}{3}=4\left(x-\frac{3}{4}\right)[/tex]
D. [tex]y-4=\frac{3}{4}\left(x-\frac{1}{3}\right)[/tex]



Answer :

To determine which equation represents a line that passes through the point [tex]\(\left(4, \frac{1}{3}\right)\)[/tex] and has a slope of [tex]\(\frac{3}{4}\)[/tex], we need to use the point-slope form of the equation of a line. The point-slope form is given by:

[tex]\[ y - y_1 = m(x - x_1) \][/tex]

where [tex]\((x_1, y_1)\)[/tex] is a point on the line and [tex]\(m\)[/tex] is the slope.

Given:
- Point: [tex]\((x_1, y_1) = \left(4, \frac{1}{3}\right)\)[/tex]
- Slope: [tex]\(m = \frac{3}{4}\)[/tex]

We substitute these values into the point-slope form equation:

[tex]\[ y - \frac{1}{3} = \frac{3}{4}(x - 4) \][/tex]

Thus, the correct equation that represents the line passing through the point [tex]\(\left(4, \frac{1}{3}\right)\)[/tex] with slope [tex]\(\frac{3}{4}\)[/tex] is:

[tex]\[ y - \frac{1}{3} = \frac{3}{4}(x - 4) \][/tex]

Therefore, the correct option among the given choices is:

[tex]\[ \boxed{2} \][/tex]

Or explicitly:
[tex]\[ y-\frac{1}{3}=\frac{3}{4}(x-4) \][/tex]