We wish to determine the moles of AgCl formed when 50.0 mL of [tex]0.250 \, \text{M} \, \text{AgNO}_3[/tex] reacts with excess [tex]\text{MgCl}_2[/tex] according to the equation below.

[tex]\[
2 \, \text{AgNO}_3(\text{aq}) + \text{MgCl}_2(\text{aq}) \rightarrow 2 \, \text{AgCl}(\text{s}) + \text{Mg}(\text{NO}_3)_2(\text{aq})
\][/tex]

In the previous step, you determined [tex]0.0125 \, \text{mol} \, \text{AgNO}_3[/tex] react.

How many moles of AgCl form during the reaction?



Answer :

Certainly! Let's break down the process to determine how many moles of AgCl are formed during the reaction.

1. Write the balanced chemical equation:
[tex]\[ 2 \, \text{AgNO}_3 (aq) + \text{MgCl}_2 (aq) \rightarrow 2 \, \text{AgCl} (s) + \text{Mg(NO}_3\text{)}_2 (aq) \][/tex]

2. Identify stoichiometry between reactants and products:
According to the balanced equation, 2 moles of AgNO[tex]\(_3\)[/tex] react to produce 2 moles of AgCl. Therefore, the ratio of AgNO[tex]\(_3\)[/tex] to AgCl is 1:1.

3. Given data:
You have already determined that there are 0.0125 moles of AgNO[tex]\(_3\)[/tex] reacting.

4. Determine moles of AgCl formed:
Since the molar ratio of AgNO[tex]\(_3\)[/tex] to AgCl is 1:1, the moles of AgCl formed will be equal to the moles of AgNO[tex]\(_3\)[/tex] reacting.

Therefore, the moles of AgCl produced are:
[tex]\[ 0.0125 \, \text{moles} \][/tex]

So, the number of moles of AgCl formed during the reaction is [tex]\(0.0125 \, \text{moles}\)[/tex].

Other Questions