The ratios are inversely proportional. Find the missing variable. If [tex]t_1 = 4[/tex], [tex]s_1 = 5[/tex], and [tex]s_2 = 2[/tex], what is the value of [tex]t_2[/tex]?

Answer:



Answer :

Certainly! Let's solve the problem step-by-step.

We are told that the ratios are inversely proportional. When two quantities are inversely proportional, their product is constant. This means if one quantity increases, the other decreases in such a way that their product remains the same.

Given:
- [tex]\( t_1 = 4 \)[/tex]
- [tex]\( s_1 = 5 \)[/tex]
- [tex]\( s_2 = 2 \)[/tex]

We need to find the value of [tex]\( t_2 \)[/tex].

Since the ratios are inversely proportional, we can write the relationship as:
[tex]\[ t_1 \cdot s_1 = t_2 \cdot s_2 \][/tex]

Substitute the given values into the equation:
[tex]\[ 4 \cdot 5 = t_2 \cdot 2 \][/tex]

Simplify the left-hand side of the equation:
[tex]\[ 20 = t_2 \cdot 2 \][/tex]

Next, solve for [tex]\( t_2 \)[/tex] by dividing both sides of the equation by 2:
[tex]\[ t_2 = \frac{20}{2} \][/tex]

Calculate the division:
[tex]\[ t_2 = 10 \][/tex]

So, the value of [tex]\( t_2 \)[/tex] is [tex]\( 10 \)[/tex].