The square root is not a real number if [tex] x=3 [/tex] and [tex] y=6 [/tex].

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Answer :

Sure, let's solve the problem of finding the square roots of [tex]\( \sqrt{x} \)[/tex] and [tex]\( \sqrt{y} \)[/tex] where [tex]\( x = 3 \)[/tex] and [tex]\( y = 6 \)[/tex].

### Step-by-Step Solution

1. Identify the given values:
- [tex]\( x = 3 \)[/tex]
- [tex]\( y = 6 \)[/tex]

2. Calculate [tex]\( \sqrt{x} \)[/tex]:
The square root of [tex]\( x = 3 \)[/tex] is:
[tex]\[ \sqrt{3} \approx 1.732 \][/tex]

3. Calculate [tex]\( \sqrt{y} \)[/tex]:
The square root of [tex]\( y = 6 \)[/tex] is:
[tex]\[ \sqrt{6} \approx 2.449 \][/tex]

4. State the results:
- The square root of 3, [tex]\( \sqrt{3} \)[/tex], is approximately 1.732.
- The square root of 6, [tex]\( \sqrt{6} \)[/tex], is approximately 2.449.

These steps show how to find and interpret the square roots of 3 and 6 respectively.