Stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. The height, [tex]h(t)[/tex], in meters (as it relates to sea level), of the sunglasses after [tex]t[/tex] seconds, is shown in the table.

Height of Sunglasses over Time

\begin{tabular}{|c|c|}
\hline
[tex]$t$[/tex] & [tex]$h(t)$[/tex] \\
\hline
0 & 10 \\
\hline
1 & 5.1 \\
\hline
2 & -9.6 \\
\hline
3 & -34.1 \\
\hline
4 & -68.4 \\
\hline
5 & -112.5 \\
\hline
6 & -166.4 \\
\hline
7 & -230.1 \\
\hline
\end{tabular}

During its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after Stefano dropped them. To the nearest meter, what is the difference in elevation between Stefano and the climber?

A. 166 meters
B. 176 meters
C. 230 meters
D. 240 meters



Answer :

To solve the problem of finding the nearest meter difference in elevation between Stefano and the climber at 6 seconds, we need to follow these steps:

1. Identify the initial height of Stefano's location:
From the given table, at [tex]\( t = 0 \)[/tex] seconds, the height ([tex]\( h(0) \)[/tex]) is 10 meters. This is Stefano's position.

2. Identify the height of the sunglasses at [tex]\( t = 6 \)[/tex] seconds:
From the table, at [tex]\( t = 6 \)[/tex] seconds, the height ([tex]\( h(6) \)[/tex]) is -166.4 meters. This is the position of the climber, as the sunglasses just passed by them.

3. Calculate the difference in elevation:
The difference in elevation is calculated by subtracting the height of the climber from Stefano's initial height:
[tex]\[ \text{ElevationDifference} = h(0) - h(6) \][/tex]
Substituting the known values:
[tex]\[ \text{ElevationDifference} = 10 - (-166.4) = 10 + 166.4 = 176.4 \text{ meters} \][/tex]

4. Round the difference to the nearest meter:
When rounding 176.4 to the nearest meter, the result is:
[tex]\[ 176 \text{ meters} \][/tex]

Therefore, the nearest meter difference in elevation between Stefano and the climber is 176 meters. Hence, the correct answer is:

[tex]\[ \boxed{176 \text{ meters}} \][/tex]