Given [tex]$f(x)=6x+2$[/tex], find [tex]$f(x-3)$[/tex].

A. [tex]f(x-3)=6x-1[/tex]
B. [tex]f(x-3)=6x-16[/tex]
C. [tex]f(x-3)=x-1[/tex]
D. [tex]f(x-3)=6x^2-16x-6[/tex]



Answer :

To find [tex]\( f(x-3) \)[/tex] for the given function [tex]\( f(x) = 6x + 2 \)[/tex], follow these steps:

1. Substitute [tex]\( x-3 \)[/tex] into the function [tex]\( f(x) \)[/tex]:
The function [tex]\( f(x) \)[/tex] is initially defined as:
[tex]\[ f(x) = 6x + 2 \][/tex]
We need to find [tex]\( f(x-3) \)[/tex]. This means wherever there is an [tex]\( x \)[/tex] in the function, we replace it with [tex]\( (x-3) \)[/tex].

2. Perform the substitution:
[tex]\[ f(x-3) = 6(x-3) + 2 \][/tex]

3. Distribute the 6:
Distribute the 6 inside the parentheses:
[tex]\[ f(x-3) = 6(x-3) + 2 = 6x - 18 + 2 \][/tex]

4. Combine like terms:
Combine the constants:
[tex]\[ f(x-3) = 6x - 18 + 2 = 6x - 16 \][/tex]

So, the final expression for [tex]\( f(x-3) \)[/tex] is:
[tex]\[ f(x-3) = 6x - 16 \][/tex]

Among the given options, the correct one is:
[tex]\( \boxed{6x - 16} \)[/tex].