Answer the following question based on the data in the table.

\begin{tabular}{|c|c|c|c|c|}
\hline
\multirow{2}{*}{\begin{tabular}{l}
Iron \\
Deficiency
\end{tabular}} & \multicolumn{4}{|c|}{Age} \\
\hline & \begin{tabular}{l}
Less than \\
20 years
\end{tabular} & 20-30 years & Above 30 years & Total \\
\hline Yes & 41 & 37 & 24 & 102 \\
\hline No & 109 & 43 & 46 & 198 \\
\hline Total & 150 & 80 & 70 & 300 \\
\hline
\end{tabular}

What is the probability that a person with an iron deficiency is 20 years or older?

A. 0.23
B. 0.34
C. 0.60



Answer :

To find the probability that a person with an iron deficiency is 20 years or older, we need to follow these steps:

1. Identify the Total Number of People with Iron Deficiency:
From the table, the total number of people with iron deficiency is 102.

2. Identify the Number of People with Iron Deficiency Who Are 20 Years or Older:
We need to consider the number of people in the 20-30 years category and the number in the above 30 years category.
- 20-30 years: [tex]\(37\)[/tex]
- Above 30 years: [tex]\(24\)[/tex]
So, the total number of people with iron deficiency who are 20 years or older is [tex]\(37 + 24 = 61\)[/tex].

3. Calculate the Probability:
The probability is given by the ratio of the number of people with iron deficiency who are 20 years or older to the total number of people with iron deficiency.
[tex]\[ \text{Probability} = \frac{\text{Number of People with Iron Deficiency Who Are 20 Years or Older}}{\text{Total Number of People with Iron Deficiency}} \][/tex]
[tex]\[ \text{Probability} = \frac{61}{102} \][/tex]

4. Simplify the Probability (if possible):
Calculating the above ratio gives approximately [tex]\(0.598\)[/tex].

Hence, the probability that a person with an iron deficiency is 20 years or older is approximately [tex]\(0.60\)[/tex].

Answer:
C. [tex]\(0.60\)[/tex]