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\begin{tabular}{|r|r|r|r|r|r|r|r|r|r|r|}
\hline & \multicolumn{1}{|c|}{A} & \multicolumn{1}{|c|}{B} & \multicolumn{1}{c|}{C} & \multicolumn{1}{c|}{D} & \multicolumn{1}{|c|}{E} & \multicolumn{1}{|c|}{F} & G & H & I & J \\
\hline 1 & 9 & 7 & 6 & 2 & 5 & 1 & 9 & & & \\
\hline 2 & 4 & 9 & 5 & 4 & 3 & 6 & 5 & & & \\
\hline 3 & 6 & 4 & 4 & 7 & 7 & 3 & 1 & & & \\
\hline 4 & 7 & 6 & 8 & 1 & 1 & 4 & 3 & & & \\
\hline 5 & 8 & 7 & 2 & 6 & 9 & 2 & 4 & & & \\
\hline 6 & 2 & 8 & 7 & 8 & 3 & 5 & 6 & & & \\
\hline 7 & 1 & 2 & 9 & 3 & 5 & 3 & 7 & & & \\
\hline 8 & 5 & 4 & 7 & 8 & 6 & 7 & 2 & & & \\
\hline 9 & 3 & 1 & 6 & 1 & 4 & 5 & 2 & & & \\
\hline
\end{tabular}

1. Multiply A6 by F3, then add C5 to the product and save the sum in [tex]H_2[/tex].
2. Find the sum of [tex]A3 + B1 + C2 + D4[/tex] and save the sum in [tex]H_4[/tex].
3. Find the sum of [tex]A9 + F2[/tex] and save the sum in [tex]H_5[/tex].
4. Add [tex]H_4[/tex] and [tex]H_5[/tex] together and save the sum in [tex]H_6[/tex].
5. If the value saved in [tex]H_6[/tex] is smaller than [tex]H_2[/tex], then swap their contents. If not, do not swap them.
6. Multiply [tex]H_2[/tex] by [tex]H_5[/tex], then subtract [tex]H_4[/tex] and store the value in [tex]I_2[/tex].

What is the value of [tex]I_2[/tex]?

A. 84
B. 74
C. 54
D. 64



Answer :

GinnyAnswer
Let's solve the question step-by-step.

### Step 1: Calculate [tex]\(H_2\)[/tex]
Multiply [tex]\(A6\)[/tex] by [tex]\(F3\)[/tex] and then add [tex]\(C5\)[/tex] to the product.

- [tex]\(A6 = 2\)[/tex]
- [tex]\(F3 = 3\)[/tex]
- [tex]\(C5 = 2\)[/tex]

Calculate the product:
[tex]\[ A6 \times F3 = 2 \times 3 = 6 \][/tex]

Now add [tex]\(C5\)[/tex]:
[tex]\[ 6 + 2 = 8 \][/tex]

So, [tex]\(H_2 = 8\)[/tex].

### Step 2: Calculate [tex]\(H_4\)[/tex]
Find the sum of [tex]\(A3 + B1 + C2 + D4\)[/tex].

- [tex]\(A3 = 6\)[/tex]
- [tex]\(B1 = 7\)[/tex]
- [tex]\(C2 = 5\)[/tex]
- [tex]\(D4 = 1\)[/tex]

Sum them up:
[tex]\[ 6 + 7 + 5 + 1 = 19 \][/tex]

So, [tex]\(H_4 = 19\)[/tex].

### Step 3: Calculate [tex]\(H_5\)[/tex]
Find the sum of [tex]\(A9 + F2\)[/tex].

- [tex]\(A9 = 3\)[/tex]
- [tex]\(F2 = 6\)[/tex]

Sum them up:
[tex]\[ 3 + 6 = 9 \][/tex]

So, [tex]\(H_5 = 9\)[/tex].

### Step 4: Calculate [tex]\(H_6\)[/tex]
Add [tex]\(H_4\)[/tex] and [tex]\(H_5\)[/tex] together.

[tex]\[ H_6 = H_4 + H_5 = 19 + 9 = 28 \][/tex]

So, [tex]\(H_6 = 28\)[/tex].

### Step 5: Comparison and Swap (if necessary)
Compare [tex]\(H_6\)[/tex] and [tex]\(H_2\)[/tex].

- [tex]\(H_2 = 8\)[/tex]
- [tex]\(H_6 = 28\)[/tex]

Since [tex]\(H_6\)[/tex] is not smaller than [tex]\(H_2\)[/tex], no swapping is needed.

### Step 6: Calculate [tex]\(I_2\)[/tex]
Multiply [tex]\(H_2\)[/tex] by [tex]\(H_5\)[/tex], then take away [tex]\(H_4\)[/tex].

[tex]\[ H_2 \times H_5 = 8 \times 9 = 72 \][/tex]

Subtract [tex]\(H_4\)[/tex]:
[tex]\[ 72 - 19 = 53 \][/tex]

So, [tex]\(I_2 = 53\)[/tex].

Given the numerical result we have obtained for each step, there seems to be a disconnect with the final question asking for the value of "12." Given no specific context other than interpreting [tex]\( I_2 \)[/tex] as the final value derived:

The correct value for [tex]\( I_2 \)[/tex] based on our calculations is:
[tex]\[ \boxed{53} \][/tex]

However, considering the options given in the question [tex]\((84, 74, 54, 64)\)[/tex], none match the calculated [tex]\( I_2 \)[/tex] value of 53.

If you are looking for [tex]\(I_2\)[/tex], it's the value we've calculated: [tex]\(53\)[/tex]. Among the provided options, the closest (though not matching) would be [tex]\(54\)[/tex].

Given the discrepancy, the exact match is [tex]\(53\)[/tex], and the practical answer from the available choices would be:
[tex]\[ \boxed{54} \][/tex]

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