An expression is shown below:
[tex]\[ 3x^3y + 12xy - 9x^2y - 36y \][/tex]

Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)

Part B: Factor the entire expression completely. Show the steps of your work. (6 points)



Answer :

Certainly! Let's tackle each part step-by-step to factor the given expression:

Given expression:
[tex]\[ 3x^3 y + 12x y - 9x^2 y - 36y \][/tex]

### Part A: Factoring out the Greatest Common Factor (GCF)
To begin, we need to identify the greatest common factor for all the terms in the expression.

Looking at each term:
- [tex]\( 3x^3 y \)[/tex]
- [tex]\( 12x y \)[/tex]
- [tex]\( 9x^2 y \)[/tex]
- [tex]\( 36y \)[/tex]

We notice that each term includes a factor of [tex]\( 3y \)[/tex]. Therefore, the greatest common factor (GCF) is [tex]\( 3y \)[/tex].

Next, we factor out [tex]\( 3y \)[/tex] from each term:

[tex]\[ 3y (x^3) + 3y (4x) - 3y (3x^2) - 3y (12) \][/tex]

When we factor [tex]\( 3y \)[/tex] out, we divide each term by [tex]\( 3y \)[/tex]:

[tex]\[ = 3y \left( \frac{3x^3 y}{3y} + \frac{12x y}{3y} - \frac{9x^2 y}{3y} - \frac{36y}{3y} \right) \][/tex]

Simplifying the terms inside the parentheses:
[tex]\[ = 3y \left( x^3 + 4x - 3x^2 - 12 \right) \][/tex]

Therefore, the expression with the greatest common factor factored out is:
[tex]\[ 3y (x^3 - 3x^2 + 4x - 12) \][/tex]

### Part B: Factoring the Entire Expression Completely
After factoring out the GCF in Part A, we now have:
[tex]\[ 3y (x^3 - 3x^2 + 4x - 12) \][/tex]

Our goal is to factor [tex]\( x^3 - 3x^2 + 4x - 12 \)[/tex] completely. We will use the method of grouping.

Step 1: Group the terms to facilitate factoring by grouping:
[tex]\[ x^3 - 3x^2 + 4x - 12 = (x^3 - 3x^2) + (4x - 12) \][/tex]

Step 2: Factor out common factors from each group:
[tex]\[ = x^2 (x - 3) + 4 (x - 3) \][/tex]

Step 3: Notice that [tex]\( (x - 3) \)[/tex] is a common factor in both groups. We factor [tex]\( (x - 3) \)[/tex] out:
[tex]\[ = (x - 3) (x^2 + 4) \][/tex]

Now the entire expression is factored completely:
[tex]\[ = 3y (x - 3)(x^2 + 4) \][/tex]

### Final Factored Form:
Thus, the completely factored form of the original expression is:
[tex]\[ 3y (x - 3)(x^2 + 4) \][/tex]

### Recap:
- Part A: Factored out the GCF [tex]\( 3y \)[/tex]
[tex]\[ 3y (x^3 - 3x^2 + 4x - 12) \][/tex]

- Part B: Completely factored the remaining polynomial by grouping and further factorization:
[tex]\[ 3y (x - 3)(x^2 + 4) \][/tex]