The hypotenuse of a [tex]45^{\circ}-45^{\circ}-90^{\circ}[/tex] triangle measures 128 cm. What is the length of one leg of the triangle?

A. 64 cm
B. [tex]64 \sqrt{2}[/tex] cm
C. 128 cm
D. [tex]128 \sqrt{2}[/tex] cm



Answer :

To solve this problem, we need to understand the properties of a [tex]\(45^{\circ}-45^{\circ}-90^{\circ}\)[/tex] triangle. In such a triangle, the legs are of equal length and are both denoted as [tex]\(a\)[/tex]. The relationship between the legs and the hypotenuse (denoted as [tex]\(c\)[/tex]) in a [tex]\(45^{\circ}-45^{\circ}-90^{\circ}\)[/tex] triangle is given by:

[tex]\[ c = a \sqrt{2} \][/tex]

Given that the hypotenuse [tex]\( c = 128 \)[/tex] cm, we can find the length of one leg [tex]\( a \)[/tex] by solving the equation:

[tex]\[ 128 = a \sqrt{2} \][/tex]

To isolate [tex]\( a \)[/tex], divide both sides by [tex]\(\sqrt{2}\)[/tex]:

[tex]\[ a = \frac{128}{\sqrt{2}} \][/tex]

To simplify this expression, we multiply the numerator and the denominator by [tex]\(\sqrt{2}\)[/tex]:

[tex]\[ a = \frac{128 \sqrt{2}}{2} \][/tex]
[tex]\[ a = 64 \sqrt{2} \][/tex]

Therefore, the length of one leg of the triangle is:

[tex]\[\boxed{64 \sqrt{2} \, \text{cm}}\][/tex]