First, let's analyze the given electron configuration: [tex]\([Ne]3s^2 3p^1\)[/tex].
1. Atomic Number Calculation:
- The configuration starts with [tex]\([Ne]\)[/tex], which represents the electron configuration of Neon. Neon has 10 electrons.
- Following that, we have [tex]\(3s^2\)[/tex], which means there are 2 electrons in the 3s orbital.
- Lastly, [tex]\(3p^1\)[/tex] means there is 1 electron in the 3p orbital.
Adding these together, we get the total number of electrons:
[tex]\[10 \, (\text{from Ne}) + 2 \, (\text{from 3s}) + 1 \, (\text{from 3p}) = 13\][/tex]
For a neutral atom, the number of electrons equals the atomic number. Therefore, this element has an atomic number of 13.
2. Identifying the Element:
- The atomic number 13 corresponds to the element Aluminum (Al) on the periodic table.
3. Determining the Group Number:
- Elements in the [tex]\(p\)[/tex]-block of the periodic table have their group number determined by the formula: [tex]\(Group\,number = 10 + \text{number of electrons in the outermost \(p\)[/tex]-orbital}\).
- Here, there is 1 electron in the 3p orbital.
Therefore, the group number is:
[tex]\[10 + 1 = 11\][/tex]
In conclusion, the element described by the electron configuration [tex]\([Ne]3s^2 3p^1\)[/tex] is found in Group 11 of the periodic table.
