As part of a class project, a university student surveyed the students in the cafeteria lunch line to look for a relationship between eye color and hair color among students. The table below contains the results of the survey.

\begin{tabular}{|c|c|c|c|c|c|}
\cline {2-6}
\multicolumn{1}{c|}{} & \multicolumn{5}{c|}{Eye Color} \\
\hline
Hair Color & Blue & Gray & Green & Brown & Marginal Totals \\
\hline
Blond & 42 & 5 & 21 & 10 & 78 \\
\hline
Red & 12 & 22 & 19 & 12 & 65 \\
\hline
Brown & 22 & 5 & 12 & 34 & 73 \\
\hline
Black & 9 & 3 & 11 & 64 & 87 \\
\hline
Marginal Totals & 85 & 35 & 63 & 120 & 303 \\
\hline
\end{tabular}

From the sample population of students with blond hair, what is the approximate value of the relative frequency of students with green eyes?

A. [tex]$\quad 0.07$[/tex]

B. 0.33

C. 0.25

D. [tex]$\quad 0.27$[/tex]



Answer :

To find the relative frequency of students with green eyes among those with blond hair, we follow these steps:

1. Identify the number of students with blond hair and green eyes:
From the table, we see that the number of students with blond hair and green eyes is [tex]\(21\)[/tex].

2. Identify the total number of students with blond hair:
From the table, we also see that the total number of students with blond hair is [tex]\(78\)[/tex].

3. Calculate the relative frequency:
The relative frequency is calculated by dividing the number of students with blond hair and green eyes by the total number of students with blond hair. Mathematically, this is given by:
[tex]\[ \text{Relative Frequency} = \frac{\text{Number of students with blond hair and green eyes}}{\text{Total number of students with blond hair}} \][/tex]
Substituting in the numbers from our table:
[tex]\[ \text{Relative Frequency} = \frac{21}{78} \][/tex]

4. Simplify the fraction:
When you divide [tex]\(21\)[/tex] by [tex]\(78\)[/tex], you get approximately:
[tex]\[ \frac{21}{78} \approx 0.2692307692307692 \][/tex]

Thus, the approximate value of the relative frequency is [tex]\(0.27\)[/tex].

Therefore, the correct answer is:
D. [tex]\(0.27\)[/tex]