Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

The cafeteria manager in an office building surveyed workers in the office building about their soup preferences. The results are shown in the two-way relative frequency table below.

[tex]\[
\begin{tabular}{|l|c|c|c|c|c|}
\cline { 2 - 6 } \multicolumn{1}{c|}{} & Lentil & Mushroom & Chicken & Tomato & Total \\
\hline Part-time & 85 & 40 & 35 & 70 & 230 \\
\hline Full-time & 25 & 55 & 65 & 125 & 270 \\
\hline Total & 110 & 95 & 100 & 195 & 500 \\
\hline
\end{tabular}
\][/tex]

Use the information provided in the table to match each description with the correct percentage of workers.

- 25.1\%
- [tex]$30.4 \%$[/tex]
- 30\%
- 20.4\%
- [tex]$22.7 \%$[/tex]
- 35\%
- 38.6\%
- 18.3\%

Percentage of workers who prefer lentil soup who are full-time
Percentage of part-time workers who prefer tomato soup
Percentage of workers who prefer chicken soup who are part-time
Percentage of full-time workers who prefer mushroom soup



Answer :

Let's pair each description with the correct percentage of workers by analyzing the given data:

1. Percentage of workers who prefer lentil soup who are full-time:
- From the table, we have 25 full-time workers who prefer lentil soup out of a total of 110 workers who prefer lentil soup.
- Therefore, the percentage is [tex]\( \frac{25}{110} \times 100 = 22.7\% \)[/tex].

2. Percentage of part-time workers who prefer tomato soup:
- From the table, we have 70 part-time workers who prefer tomato soup out of a total of 230 part-time workers.
- Therefore, the percentage is [tex]\( \frac{70}{230} \times 100 = 30.4\% \)[/tex].

3. Percentage of workers who prefer chicken soup who are part-time:
- From the table, we have 35 part-time workers who prefer chicken soup out of a total of 100 workers who prefer chicken soup.
- Therefore, the percentage is [tex]\( \frac{35}{100} \times 100 = 35\% \)[/tex].

4. Percentage of full-time workers who prefer mushroom soup:
- From the table, we have 55 full-time workers who prefer mushroom soup out of a total of 270 full-time workers.
- Therefore, the percentage is [tex]\( \frac{55}{270} \times 100 = 20.4\% \)[/tex].

So, the pairs are as follows:

1. Percentage of workers who prefer lentil soup who are full-time: [tex]\( 22.7\% \)[/tex]
2. Percentage of part-time workers who prefer tomato soup: [tex]\( 30.4\% \)[/tex]
3. Percentage of workers who prefer chicken soup who are part-time: [tex]\( 35\% \)[/tex]
4. Percentage of full-time workers who prefer mushroom soup: [tex]\( 20.4\% \)[/tex]