```latex
\begin{tabular}{|l|c|c|c|c|c|c|c|c|c|c|c|}
\hline Base & 8 & 2 & 10 & 40 & 6 & 10 & 73 & 90 & 98 & 80 & 60 \\
\hline Exponente & 2 & 5 & & 3 & 4 & & 2 & 3 & 3 & & \\
\hline Valor & 64 & 32 & 100 & & 1296 & & 5329 & 729000 & 941192 & 6400 & 3600 \\
\hline
\end{tabular}

\begin{tabular}{|l|l|l|l|l|l|l|l|l|l|l|l|}
\hline Número & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 \\
\hline Cuadrado & 4 & 9 & 16 & 25 & 36 & 49 & 64 & 81 & 100 & 121 & 144 \\
\hline Cubo & 8 & 27 & 64 & 125 & 216 & 343 & 512 & 729 & 1000 & 1331 & 1728 \\
\hline
\end{tabular}
```



Answer :

To solve the problem, we need to fill in the missing values in the tables by performing the necessary calculations.

### Part 1: Complete the first table

We begin by filling in the missing 'valor' using the provided 'Base' and 'Exponente'. Specifically, when both 'Base' and 'Exponente' are present, 'valor' is calculated as [tex]\( \text{Base}^{\text{Exponente}} \)[/tex]:

1. For Base = 40 and Exponente = 3:
[tex]\[ \text{valor} = 40^3 = 64000 \][/tex]

2. For Base = 6 and Exponente = 4:
[tex]\[ \text{valor} = 6^4 = 1296 \][/tex]

3. For Base = 90 and Exponente = 3:
[tex]\[ \text{valor} = 90^3 = 729000 \][/tex]

4. For Base = 98 and Exponente = 3:
[tex]\[ \text{valor} = 98^3 = 941192 \][/tex]

Now, after the calculations, the completed table is:
\begin{verbatim}
|---- Base ----| 8 | 2 | 10 | 40 | 6 | 10 | 73 | 90 | 98 | 80 | 60 |
|-- Exponente -| 2 | 5 | | 3 | 4 | | 2 | 3 | 3 | | |
|---- valor ---| 64 | 32 |100 |64000|1296 | |4900|729000|941192| 6400|3600 |
\end{verbatim}

### Part 2: Complete the second table

Next, we fill in the missing 'suadrado' and 'cubo' values for each 'Jumero' from 2 to 12:

For 'suadrado', which is the square of each 'Jumero' ([tex]\( \text{suadrado} = \text{Jumero}^2 \)[/tex]):
\begin{itemize}
\item [tex]\( \text{Jumero} = 2 \rightarrow 2^2 = 4 \)[/tex]
\item [tex]\( \text{Jumero} = 3 \rightarrow 3^2 = 9 \)[/tex]
\item [tex]\( \text{Jumero} = 4 \rightarrow 4^2 = 16 \)[/tex]
\item [tex]\( \text{Jumero} = 5 \rightarrow 5^2 = 25 \)[/tex]
\item [tex]\( \text{Jumero} = 6 \rightarrow 6^2 = 36 \)[/tex]
\item [tex]\( \text{Jumero} = 7 \rightarrow 7^2 = 49 \)[/tex]
\item [tex]\( \text{Jumero} = 8 \rightarrow 8^2 = 64 \)[/tex]
\item [tex]\( \text{Jumero} = 9 \rightarrow 9^2 = 81 \)[/tex]
\item [tex]\( \text{Jumero} = 10 \rightarrow 10^2 = 100 \)[/tex]
\item [tex]\( \text{Jumero} = 11 \rightarrow 11^2 = 121 \)[/tex]
\item [tex]\( \text{Jumero} = 12 \rightarrow 12^2 = 144 \)[/tex]
\end{itemize}

For 'cubo', which is the cube of each 'Jumero' ([tex]\( \text{cubo} = \text{Jumero}^3 \)[/tex]):
\begin{itemize}
\item [tex]\( \text{Jumero} = 2 \rightarrow 2^3 = 8 \)[/tex]
\item [tex]\( \text{Jumero} = 3 \rightarrow 3^3 = 27 \)[/tex]
\item [tex]\( \text{Jumero} = 4 \rightarrow 4^3 = 64 \)[/tex]
\item [tex]\( \text{Jumero} = 5 \rightarrow 5^3 = 125 \)[/tex]
\item [tex]\( \text{Jumero} = 6 \rightarrow 6^3 = 216 \)[/tex]
\item [tex]\( \text{Jumero} = 7 \rightarrow 7^3 = 343 \)[/tex]
\item [tex]\( \text{Jumero} = 8 \rightarrow 8^3 = 512 \)[/tex]
\item [tex]\( \text{Jumero} = 9 \rightarrow 9^3 = 729 \)[/tex]
\item [tex]\( \text{Jumero} = 10 \rightarrow 10^3 = 1000 \)[/tex]
\item [tex]\( \text{Jumero} = 11 \rightarrow 11^3 = 1331 \)[/tex]
\item [tex]\( \text{Jumero} = 12 \rightarrow 12^3 = 1728 \)[/tex]
\end{itemize}

Now, after the calculations, the completed table is:
\begin{verbatim}
|----- Jumero ----| 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
|---- suadrado ---| 4 | 9 | 16| 25 | 36 | 49 | 64 | 81 |100 |121 |144 |
|------ Cubo -----| 8 | 27| 64| 125| 216| 343| 512| 729|1000|1331 |1728 |
\end{verbatim}

By following these steps methodically, we have successfully completed both tables.