Answer :
Certainly! Let's complete the table step-by-step.
We start with the given table:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
Next, we'll fill in the second row by performing the operations indicated:
1. Initial Value (-2): We begin with -2 in the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & -2 & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
2. First Operation: Add 8 to -2:
[tex]\[ -2 + 8 = 6 \][/tex]
So we place 6 in the next cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
3. Second Operation: Add 4 to 6:
[tex]\[ 6 + 4 = 10 \][/tex]
So we place 10 in the next cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
4. Third Operation: Add -3 to 10:
[tex]\[ 10 + (-3) = 7 \][/tex]
So we place 7 in the next cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
5. Fourth Operation: Add -5 to 7:
[tex]\[ 7 + (-5) = 2 \][/tex]
So we place 2 in the final cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & 2 \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
The resulting table is now complete and reads as follows:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & 2 \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
This showcases how we completed the row using a series of additions.
We start with the given table:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
Next, we'll fill in the second row by performing the operations indicated:
1. Initial Value (-2): We begin with -2 in the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & -2 & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
2. First Operation: Add 8 to -2:
[tex]\[ -2 + 8 = 6 \][/tex]
So we place 6 in the next cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
3. Second Operation: Add 4 to 6:
[tex]\[ 6 + 4 = 10 \][/tex]
So we place 10 in the next cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
4. Third Operation: Add -3 to 10:
[tex]\[ 10 + (-3) = 7 \][/tex]
So we place 7 in the next cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
5. Fourth Operation: Add -5 to 7:
[tex]\[ 7 + (-5) = 2 \][/tex]
So we place 2 in the final cell of the second row:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & 2 \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
The resulting table is now complete and reads as follows:
[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & 2 \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]
This showcases how we completed the row using a series of additions.