Answered

The original tabular content appears to have an incomplete or unclear intention. I'll format it to make it readable and meaningful within the context of a tabular presentation:

\begin{tabular}{|c|c|c|c|c|}
\hline
\hline+ & 8 & 4 & -3 & -5 \\
\hline
-2 & [tex]$-2+8=+6$[/tex] & & & \\
\hline
6 & & & & \\
\hline
0 & & & & \\
\hline
-4 & & & & \\
\hline
\end{tabular}

If the table is intended to perform calculations or illustrate a concept, more context or corrections are needed to clarify the purpose.



Answer :

GinnyAnswer
Certainly! Let's complete the table step-by-step.

We start with the given table:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

Next, we'll fill in the second row by performing the operations indicated:

1. Initial Value (-2): We begin with -2 in the second row:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & -2 & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

2. First Operation: Add 8 to -2:

[tex]\[ -2 + 8 = 6 \][/tex]

So we place 6 in the next cell of the second row:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

3. Second Operation: Add 4 to 6:

[tex]\[ 6 + 4 = 10 \][/tex]

So we place 10 in the next cell of the second row:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

4. Third Operation: Add -3 to 10:

[tex]\[ 10 + (-3) = 7 \][/tex]

So we place 7 in the next cell of the second row:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

5. Fourth Operation: Add -5 to 7:

[tex]\[ 7 + (-5) = 2 \][/tex]

So we place 2 in the final cell of the second row:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & 2 \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

The resulting table is now complete and reads as follows:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \hline+ & 8 & 4 & -3 & -5 \\ \hline-2 & 6 & 10 & 7 & 2 \\ \hline 6 & & & & \\ \hline 0 & & & & \\ \hline-4 & & & & \\ \hline \end{tabular} \][/tex]

This showcases how we completed the row using a series of additions.