Answer :
Certainly! Let's simplify the expression [tex]\(6y + y + 4y\)[/tex] by combining like terms. Here are the steps:
1. Identify the like terms:
All the terms [tex]\(6y\)[/tex], [tex]\(y\)[/tex], and [tex]\(4y\)[/tex] have the variable [tex]\(y\)[/tex], so they are like terms.
2. Rewrite the expression by grouping the coefficients:
[tex]\(6y + y + 4y\)[/tex]
3. Combine the coefficients:
Add the coefficients of [tex]\(y\)[/tex]:
- The coefficient of the first term is 6.
- The coefficient of the second term is 1 (since [tex]\(y\)[/tex] is the same as [tex]\(1y\)[/tex]).
- The coefficient of the third term is 4.
So, we have:
[tex]\[ 6 + 1 + 4 \][/tex]
Adding these together:
[tex]\[ 6 + 1 = 7 \][/tex]
[tex]\[ 7 + 4 = 11 \][/tex]
4. Write the combined term:
Now, multiply the combined coefficient by [tex]\(y\)[/tex]:
[tex]\[ 11y \][/tex]
Thus, the simplified form of [tex]\(6y + y + 4y\)[/tex] is:
[tex]\[ \boxed{11y} \][/tex]
1. Identify the like terms:
All the terms [tex]\(6y\)[/tex], [tex]\(y\)[/tex], and [tex]\(4y\)[/tex] have the variable [tex]\(y\)[/tex], so they are like terms.
2. Rewrite the expression by grouping the coefficients:
[tex]\(6y + y + 4y\)[/tex]
3. Combine the coefficients:
Add the coefficients of [tex]\(y\)[/tex]:
- The coefficient of the first term is 6.
- The coefficient of the second term is 1 (since [tex]\(y\)[/tex] is the same as [tex]\(1y\)[/tex]).
- The coefficient of the third term is 4.
So, we have:
[tex]\[ 6 + 1 + 4 \][/tex]
Adding these together:
[tex]\[ 6 + 1 = 7 \][/tex]
[tex]\[ 7 + 4 = 11 \][/tex]
4. Write the combined term:
Now, multiply the combined coefficient by [tex]\(y\)[/tex]:
[tex]\[ 11y \][/tex]
Thus, the simplified form of [tex]\(6y + y + 4y\)[/tex] is:
[tex]\[ \boxed{11y} \][/tex]