Answer:
0.133 g
Explanation:
We are given that a chemist adds 525.0 mL of a calcium sulfate solution to a flask.
We know that the density of calcium sulfate is 0.253 g/L.
We want to know how much calcium sulfate (in grams) was added to the flask in three significant figures.
First, convert from mL to L.
525.0 mL => 0.5250 L
Now, multiply this volume by the density to get the amount of grams.
[tex]0.5250 L * \frac{0.253 g}{1 L } = 0.133 g[/tex] (rounded to three significant figures).