[tex]$\$[/tex]8500[tex]$ are deposited in an account with $[/tex]7\%[tex]$ interest rate, compounded continuously. What is the balance after 16 years?

\[ F = \$[/tex][?] \]

Round to the nearest cent.



Answer :

To determine the balance after 16 years for an initial deposit of \[tex]$8500 in an account with an annual interest rate of 7% compounded continuously, we can use the formula for continuous compounding. The formula is: \[ F = Pe^{rt} \] where: - \( P \) is the principal amount (initial deposit), - \( r \) is the annual interest rate (expressed as a decimal), - \( t \) is the time the money is invested for (in years), - \( e \) is the base of the natural logarithm (approximately equal to 2.71828), - \( F \) is the future value of the investment, including interest. Given the values: - \( P = 8500 \), - \( r = 0.07 \), - \( t = 16 \), we can plug these values into the formula: \[ F = 8500 \times e^{0.07 \times 16} \] Calculating the exponent first: \[ 0.07 \times 16 = 1.12 \] Now, we compute \( e^{1.12} \): \[ e^{1.12} \approx 3.065 \] Multiplying by the principal: \[ F \approx 8500 \times 3.065 = 26051.26 \] Therefore, the balance after 16 years, rounded to the nearest cent, is: \[ F = \$[/tex]26051.26
\]

So, the balance after 16 years is \$26051.26.