Answer :
To find the value of [tex]\( x \)[/tex] that makes the equation [tex]\( 6x + 3 = 45 \)[/tex] true, follow these steps:
1. Isolate the term with [tex]\( x \)[/tex]:
Begin by eliminating the constant term on the left side of the equation. The constant term here is 3. To do this, subtract 3 from both sides of the equation.
[tex]\[ 6x + 3 - 3 = 45 - 3 \][/tex]
Simplifying both sides, we have:
[tex]\[ 6x = 42 \][/tex]
2. Solve for [tex]\( x \)[/tex]:
Now, to isolate [tex]\( x \)[/tex], divide both sides of the equation by the coefficient of [tex]\( x \)[/tex], which is 6.
[tex]\[ \frac{6x}{6} = \frac{42}{6} \][/tex]
Simplifying the right side, we get:
[tex]\[ x = 7 \][/tex]
Therefore, the value of [tex]\( x \)[/tex] that satisfies the equation [tex]\( 6x + 3 = 45 \)[/tex] is:
[tex]\[ x = 7 \][/tex]
1. Isolate the term with [tex]\( x \)[/tex]:
Begin by eliminating the constant term on the left side of the equation. The constant term here is 3. To do this, subtract 3 from both sides of the equation.
[tex]\[ 6x + 3 - 3 = 45 - 3 \][/tex]
Simplifying both sides, we have:
[tex]\[ 6x = 42 \][/tex]
2. Solve for [tex]\( x \)[/tex]:
Now, to isolate [tex]\( x \)[/tex], divide both sides of the equation by the coefficient of [tex]\( x \)[/tex], which is 6.
[tex]\[ \frac{6x}{6} = \frac{42}{6} \][/tex]
Simplifying the right side, we get:
[tex]\[ x = 7 \][/tex]
Therefore, the value of [tex]\( x \)[/tex] that satisfies the equation [tex]\( 6x + 3 = 45 \)[/tex] is:
[tex]\[ x = 7 \][/tex]