DAY 5
Ratios/Punctuation

Max is making some trail mix. The ratio of nuts to pieces of dried fruit is 3:1. Complete the ratio table to show equivalent ratios. Then, graph the ratios on the coordinate plane.

\begin{tabular}{|c|c|}
\hline
Nuts [tex]$(x)$[/tex] & Fruit [tex]$(y)$[/tex] \\
\hline
3 & 1 \\
\hline
6 & 2 \\
\hline
9 & 3 \\
\hline
12 & 4 \\
\hline
15 & 5 \\
\hline
\end{tabular}



Answer :

Alright, let's solve it step-by-step.

We are given a ratio of nuts to pieces of dried fruit as 3:1. This means for every 3 nuts, there is 1 piece of dried fruit.

Now let's fill in the ratio table step by step to show equivalent ratios:

### Step-by-Step Calculation:

1. First Ratio:
- Nuts: 3
- Fruit: 1

The first pair is already given in the table.

2. Second Ratio:
- Nuts: 6
- Fruit: 2

The second pair is already given in the table.

3. Third Ratio:
- By maintaining the ratio 3:1, if we increase the number of nuts by another set of 3 (from the first ratio), we get 3 + 3 = 6 nuts. Since this is already our second set, let's do it again:
- Nuts: 6 + 3 = 9
- Fruit: 2 + 1 = 3

So, the third pair is (9, 3).

4. Fourth Ratio:
- Again, maintaining the 3:1 ratio,
- Nuts: 9 + 3 = 12
- Fruit: 3 + 1 = 4

So, the fourth pair is (12, 4).

5. Fifth Ratio:
- Continuing with the same ratio,
- Nuts: 12 + 3 = 15
- Fruit: 4 + 1 = 5

So, the fifth pair is (15, 5).

Now the completed ratio table should look like this:

[tex]\[ \begin{tabular}{|c|c|} \hline Nuts $(x)$ & Fruit $(y)$ \\ \hline 3 & 1 \\ \hline 6 & 2 \\ \hline 9 & 3 \\ \hline 12 & 4 \\ \hline 15 & 5 \\ \hline \end{tabular} \][/tex]

### Graphing on the Coordinate Plane:

To graph these ratios, plot the points on a coordinate plane with the number of nuts on the x-axis and the number of pieces of dried fruit on the y-axis. The points to plot are:

- (3, 1)
- (6, 2)
- (9, 3)
- (12, 4)
- (15, 5)

These points will lie in a straight line, demonstrating the constant ratio relationship between the number of nuts and pieces of dried fruit.