To find the probability that a person with an iron deficiency is 20 years or older, we will follow these steps:
1. Identify the relevant data from the table:
- Number of people with iron deficiency who are 20-30 years old: 37
- Number of people with iron deficiency who are above 30 years old: 24
- Total number of people with iron deficiency: 102
2. Calculate the total number of people with iron deficiency who are 20 years or older:
[tex]\[
\text{People with iron deficiency who are 20 years or older} = \text{People with iron deficiency aged 20-30} + \text{People with iron deficiency aged above 30}
\][/tex]
[tex]\[
\text{People with iron deficiency who are 20 years or older} = 37 + 24 = 61
\][/tex]
3. Determine the probability that a person with an iron deficiency is 20 years or older:
[tex]\[
\text{Probability} = \frac{\text{Number of people with iron deficiency aged 20 years or older}}{\text{Total number of people with iron deficiency}}
\][/tex]
[tex]\[
\text{Probability} = \frac{61}{102}
\][/tex]
4. Simplify the probability to a decimal:
[tex]\[
\frac{61}{102} \approx 0.598
\][/tex]
Thus, the probability that a person with an iron deficiency is 20 years or older is approximately [tex]\( 0.598 \)[/tex].
5. Round and select the closest given option:
Given the choices:
- A) 0.23
- B) 0.34
- C) 0.60
- D) 0.78
The closest option to 0.598 is [tex]\( 0.60 \)[/tex].
Therefore, the correct answer is:
C. 0.60
