Find the vertical asymptote.

[tex]\[
\begin{array}{l}
y = \frac{3x - 6}{x + 2} \\
x = [?]
\end{array}
\][/tex]

Hint: When is the function undefined? What number makes the denominator zero?



Answer :

To find the vertical asymptote of the function [tex]\( y = \frac{3x - 6}{x + 2} \)[/tex], we need to determine where the function is undefined. A function is undefined where its denominator is equal to zero because division by zero is undefined in mathematics.

Let's identify the value of [tex]\( x \)[/tex] that makes the denominator zero:

1. Start with the denominator of the function:
[tex]\[ x + 2 \][/tex]

2. Set the denominator equal to zero to find the value of [tex]\( x \)[/tex]:
[tex]\[ x + 2 = 0 \][/tex]

3. Solve the equation for [tex]\( x \)[/tex] by isolating [tex]\( x \)[/tex]:
[tex]\[ x = -2 \][/tex]

Therefore, the function [tex]\( y = \frac{3x - 6}{x + 2} \)[/tex] is undefined at [tex]\( x = -2 \)[/tex].

As a result, the vertical asymptote of the function occurs at:
[tex]\[ x = -2 \][/tex]

Thus, the vertical asymptote is [tex]\( x = -2 \)[/tex].

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