Answer :

Certainly! Let's solve the problem step-by-step.

We need to find the value of [tex]\( T \)[/tex] for the given expression:

[tex]\[ T = \frac{\frac{3}{4} + \frac{2}{3}}{\frac{2}{3} + T} \][/tex]

### Step 1: Calculate the Numerator

First, we'll simplify the numerator:

[tex]\[ \frac{3}{4} + \frac{2}{3} \][/tex]

To add these two fractions, we need a common denominator. The least common multiple (LCM) of 4 and 3 is 12.

Convert [tex]\(\frac{3}{4}\)[/tex] to a fraction with denominator 12:
[tex]\[ \frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12} \][/tex]

Convert [tex]\(\frac{2}{3}\)[/tex] to a fraction with denominator 12:
[tex]\[ \frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12} \][/tex]

Now add the fractions:
[tex]\[ \frac{9}{12} + \frac{8}{12} = \frac{17}{12} \][/tex]

So, the numerator is [tex]\( \frac{17}{12} \)[/tex].

### Step 2: Calculate the Denominator

Next, let's incorporate [tex]\( T \)[/tex] into the denominator:
[tex]\[ \frac{2}{3} + \frac{17}{12} \][/tex]

First, let’s simplify [tex]\( \frac{2}{3} \)[/tex] to a fraction with denominator 12:
[tex]\[ \frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12} \][/tex]

Now add [tex]\(\frac{8}{12}\)[/tex] and [tex]\(\frac{17}{12}\)[/tex]:
[tex]\[ \frac{8}{12} + \frac{17}{12} = \frac{25}{12} \][/tex]

So, the denominator becomes [tex]\( \frac{25}{12} \)[/tex].

### Step 3: Simplify the Fraction

Now we have:
[tex]\[ T = \frac{\frac{17}{12}}{\frac{25}{12}} \][/tex]

Since both the numerator and the denominator have the same denominator (12), we can simplify this by dividing the numerators directly:
[tex]\[ T = \frac{17}{25} \][/tex]

### Step 4: Verify the Simplification

For a fraction [tex]\( \frac{a}{b} \)[/tex], if both the numerator and the denominator are divided by the same value, we get:
[tex]\[ \frac{\frac{a \cdot k}{d}}{\frac{b \cdot k}{d}} = \frac{a}{b} \][/tex]

Applying this principle to our fraction, we get:
[tex]\[ T = \frac{17}{25} \][/tex]

### Conclusion

Hence, the calculated value of [tex]\( T \)[/tex] is:
[tex]\[ T = 0.68 \][/tex]

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