Answer :
To determine the conversion factor for converting moles of Cr (chromium) to moles of [tex]\( \text{CrCl}_3 \)[/tex] (chromium(III) chloride) using the given balanced chemical equation:
[tex]\[ 2 \text{Cr} + 3 \text{Cl}_2 \rightarrow 2 \text{CrCl}_3 \][/tex]
follow these steps:
1. Identify the Mole Ratio:
The balanced equation tells you the coefficients of the reactants and products. These coefficients represent the ratio in which the substances react and are produced.
2. Coefficients for Chromium and Chromium(III) Chloride:
From the balanced equation:
- The coefficient for Cr is 2.
- The coefficient for [tex]\( \text{CrCl}_3 \)[/tex] is also 2.
3. Determine the Mole Ratio:
To find the mole ratio of Cr to [tex]\( \text{CrCl}_3 \)[/tex], you divide the coefficient of [tex]\( \text{CrCl}_3 \)[/tex] by the coefficient of Cr:
[tex]\[ \frac{\text{Coefficient of } \text{CrCl}_3}{\text{Coefficient of Cr}} = \frac{2}{2} = 1 \][/tex]
Hence, for every 1 mole of Cr, 1 mole of [tex]\( \text{CrCl}_3 \)[/tex] is produced.
Therefore, the conversion factor you would use to convert from moles of Cr to moles of [tex]\( \text{CrCl}_3 \)[/tex] is 1.
[tex]\[ 2 \text{Cr} + 3 \text{Cl}_2 \rightarrow 2 \text{CrCl}_3 \][/tex]
follow these steps:
1. Identify the Mole Ratio:
The balanced equation tells you the coefficients of the reactants and products. These coefficients represent the ratio in which the substances react and are produced.
2. Coefficients for Chromium and Chromium(III) Chloride:
From the balanced equation:
- The coefficient for Cr is 2.
- The coefficient for [tex]\( \text{CrCl}_3 \)[/tex] is also 2.
3. Determine the Mole Ratio:
To find the mole ratio of Cr to [tex]\( \text{CrCl}_3 \)[/tex], you divide the coefficient of [tex]\( \text{CrCl}_3 \)[/tex] by the coefficient of Cr:
[tex]\[ \frac{\text{Coefficient of } \text{CrCl}_3}{\text{Coefficient of Cr}} = \frac{2}{2} = 1 \][/tex]
Hence, for every 1 mole of Cr, 1 mole of [tex]\( \text{CrCl}_3 \)[/tex] is produced.
Therefore, the conversion factor you would use to convert from moles of Cr to moles of [tex]\( \text{CrCl}_3 \)[/tex] is 1.