A regular octagon has an apothem measuring 10 in. and a perimeter of 66.3 in.

What is the area of the octagon, rounded to the nearest square inch?

A. 88 in.[tex]$^2$[/tex]
B. 175 in.[tex]$^2$[/tex]
C. 332 in.[tex]$^2$[/tex]
D. 700 in.[tex]$^2$[/tex]



Answer :

To find the area of a regular octagon, you can use the formula for the area of a regular polygon:

[tex]\[ \text{Area} = \frac{1}{2} \times \text{Apothem} \times \text{Perimeter} \][/tex]

Here, we are given:
- The apothem (a) = 10 inches
- The perimeter (P) = 66.3 inches

Let's plug these values into the formula:

1. First, calculate the product of the apothem and the perimeter:
[tex]\[ \text{Product} = 10 \times 66.3 = 663 \][/tex]

2. Next, multiply this product by [tex]\(\frac{1}{2}\)[/tex]:
[tex]\[ \text{Area} = \frac{1}{2} \times 663 = 331.5 \][/tex]

So, the area of the regular octagon is 331.5 square inches.

3. Finally, we need to round this result to the nearest square inch:
[tex]\[ \text{Rounded Area} = 332 \text{ square inches} \][/tex]

Therefore, the area of the octagon, rounded to the nearest square inch, is:

332 square inches

So, the correct option is:
[tex]\[ \boxed{332 \text{ in}^2} \][/tex]