To solve this problem, we need to determine the probability of drawing a ball that is not white from a bag containing red, white, and green balls.
1. Calculate the total number of balls:
- The bag contains:
- 4 red balls
- 6 white balls
- 3 green balls
- The total number of balls is:
[tex]\[
\text{Total balls} = 4 + 6 + 3 = 13
\][/tex]
2. Calculate the number of balls that are not white:
- The number of white balls is 6.
- Therefore, the number of balls that are not white is:
[tex]\[
\text{Non-white balls} = \text{Total balls} - \text{White balls} = 13 - 6 = 7
\][/tex]
3. Calculate the probability of drawing a non-white ball:
- The probability of an event is given by the ratio of the number of favorable outcomes to the total number of possible outcomes.
- Here, the favorable outcomes are drawing one of the non-white balls (which are 7), and the total possible outcomes are drawing any of the 13 balls. Therefore:
[tex]\[
\text{Probability (non-white ball)} = \frac{\text{Non-white balls}}{\text{Total balls}} = \frac{7}{13}
\][/tex]
Therefore, the probability that a randomly drawn ball is not white is [tex]\(\frac{7}{13}\)[/tex].
The correct answer is not listed in the options provided in the question. If this was an official question, it might contain a mistake. Nevertheless, based on our correct calculations, the answer remains:
[tex]\[ \frac{7}{13} \][/tex]
