Answer :

Certainly! To solve the equation [tex]\(4^{x-3}=8\)[/tex], let's work through the problem step-by-step.

1. Understand the Form of the Equation:

The given equation is [tex]\(4^{x-3} = 8\)[/tex].

2. Express Both Sides with the Same Base:

The left side, [tex]\(4^{x-3}\)[/tex], is already in terms of base 4. We should try to express [tex]\(8\)[/tex] with a related base for simpler calculations. Notice that:

[tex]\[ 4 = 2^2 \quad \text{and} \quad 8 = 2^3 \][/tex]

Thus, we can rewrite [tex]\(4^{x-3}\)[/tex] using base 2:

[tex]\[ 4 = 2^2 \Rightarrow 4^{x-3} = (2^2)^{x-3} = 2^{2(x-3)} = 2^{2x-6} \][/tex]

So our equation becomes:

[tex]\[ 2^{2x-6} = 2^3 \][/tex]

3. Set the Exponents Equal:

Since we now have the same base (2) on both sides of the equation, we can equate the exponents:

[tex]\[ 2x - 6 = 3 \][/tex]

4. Solve the Equation for [tex]\(x\)[/tex]:

To isolate [tex]\(x\)[/tex], follow these steps:

[tex]\[ 2x - 6 = 3 \][/tex]

Add 6 to both sides:

[tex]\[ 2x = 9 \][/tex]

Divide by 2:

[tex]\[ x = \frac{9}{2} \][/tex]

So, one solution to the equation [tex]\(4^{x-3} = 8\)[/tex] is [tex]\( x = \frac{9}{2} \)[/tex].

5. Consider Complex Solutions:

In many exponential equations, there can also be solutions involving complex numbers. By analyzing such solutions, we find another form:

[tex]\[ \left( \frac{\log(512)}{2} + \frac{i \pi}{\log(2)} \right) \][/tex]

Thus, the complete solutions to the equation are:

[tex]\[ x = \frac{9}{2} \quad \text{and} \quad x = \left( \frac{\log(512)}{2} + \frac{i \pi}{\log(2)} \right) \][/tex]

Conclusion:
On a graph, the real solution [tex]\(\frac{9}{2}\)[/tex] (which is 4.5) would be shown as the point where the curve of [tex]\(4^{x-3}\)[/tex] intersects the horizontal line [tex]\(y=8\)[/tex]. The complex solution usually is not represented on a simple Cartesian graph but is noted for completeness.

Therefore, the graph that accurately represents the solution will show an intersection at [tex]\( x = \frac{9}{2} \)[/tex].