To find the sum of [tex]\(2 \frac{7}{9} + 1 \frac{3}{8}\)[/tex], we will follow these steps:
1. Convert the mixed numbers to improper fractions:
- For [tex]\(2 \frac{7}{9}\)[/tex]:
[tex]\[
2 \frac{7}{9} = 2 + \frac{7}{9} = \frac{2 \times 9}{9} + \frac{7}{9} = \frac{18}{9} + \frac{7}{9} = \frac{25}{9}
\][/tex]
- For [tex]\(1 \frac{3}{8}\)[/tex]:
[tex]\[
1 \frac{3}{8} = 1 + \frac{3}{8} = \frac{1 \times 8}{8} + \frac{3}{8} = \frac{8}{8} + \frac{3}{8} = \frac{11}{8}
\][/tex]
2. Convert the improper fractions to decimal form for easier addition:
- [tex]\(\frac{25}{9} \approx 2.7777777777777777\)[/tex]
- [tex]\(\frac{11}{8} = 1.375\)[/tex]
3. Add the decimal forms of the improper fractions:
[tex]\[
2.7777777777777777 + 1.375 = 4.152777777777778
\][/tex]
Therefore, the sum of [tex]\(2 \frac{7}{9} + 1 \frac{3}{8}\)[/tex] is approximately [tex]\(4.152777777777778\)[/tex].
