Practice - Solving for a Specific Variable

Check Your Understanding - Question 1 of 4

Solve this equation for [tex]$x$[/tex] in terms of [tex]$y$[/tex].

[tex]2x - 8y = 12[/tex]

A. [tex]x = 4y + 12[/tex]
B. [tex]x = 4y + 6[/tex]
C. [tex]x = 8y + 6[/tex]
D. [tex]y = \frac{1}{4}x - \frac{3}{2}[/tex]



Answer :

Let's solve the equation [tex]\( 2x - 8y = 12 \)[/tex] for [tex]\( x \)[/tex] in terms of [tex]\( y \)[/tex] step by step.

1. Starting with the given equation:
[tex]\[ 2x - 8y = 12 \][/tex]

2. Isolate the [tex]\( x \)[/tex]-term on one side of the equation.
To do this, we can add [tex]\( 8y \)[/tex] to both sides of the equation to remove the [tex]\( -8y \)[/tex] term from the left side. This is done to move [tex]\( y \)[/tex] to the right side:
[tex]\[ 2x = 8y + 12 \][/tex]

3. Solve for [tex]\( x \)[/tex] by dividing both sides of the equation by the coefficient of [tex]\( x \)[/tex].
The coefficient of [tex]\( x \)[/tex] is [tex]\( 2 \)[/tex], so we divide both sides by [tex]\( 2 \)[/tex]:
[tex]\[ x = \frac{8y + 12}{2} \][/tex]

4. Simplify the right side of the equation.
Divide each term in the numerator by [tex]\( 2 \)[/tex]:
[tex]\[ x = \frac{8y}{2} + \frac{12}{2} \][/tex]
Simplifying further, we get:
[tex]\[ x = 4y + 6 \][/tex]

Therefore, the correct answer is:

[tex]\[ \boxed{x = 4y + 6} \][/tex]

So, the answer is B. [tex]\( x = 4y + 6 \)[/tex].