Answered

Using the Law of Sines for the Ambiguous Case

[tex]$\Delta JKL$[/tex] has [tex]$j = 7$[/tex], [tex]$k = 11$[/tex], and [tex]$m \angle J = 18^{\circ}$[/tex]. Complete the statements to determine all possible measures of angle [tex]$K$[/tex].

Triangle [tex]$JKL$[/tex] meets the [tex]$\square$[/tex] criteria, which means it is the ambiguous case.

Substitute the known values into the Law of Sines: [tex]$\frac{\sin \left(18^{\circ}\right)}{7} = \frac{\sin (x)}{11}$[/tex].

Cross multiply: [tex]$11 \sin \left(18^{\circ}\right) = \square$[/tex].

Solve for the measure of angle [tex]$K$[/tex], and use a calculator to determine the value.

Round to the nearest degree: [tex]$m \angle K \approx \square$[/tex].

However, because this is the ambiguous case, the measure of angle [tex]$K$[/tex] could also be [tex]$\square$[/tex].



Answer :

Sure, let's complete the statements step by step.

Given:
[tex]\( j = 7 \)[/tex]
[tex]\( k = 11 \)[/tex]
* [tex]\( \angle J = 18^\circ \)[/tex]

Step-by-Step Solution:

1. Identify the Ambiguous Case Criteria:
Triangle JKL meets the SSA (Side-Side-Angle) criteria, which means it is the ambiguous case. This situation occurs in a triangle where two sides and one non-included angle are known, and this can potentially yield two different triangles.

2. Law of Sines Setup:
Substitute the known values into the Law of Sines:
[tex]\[ \frac{\sin(18^\circ)}{7} = \frac{\sin(K)}{11} \][/tex]

3. Cross Multiply to Isolate [tex]\(\sin(K)\)[/tex]:
To find [tex]\(\sin(K)\)[/tex], cross multiply:
[tex]\[ 11 \sin(18^\circ) = 7 \sin(K) \][/tex]

4. Solve for [tex]\(\sin(K)\)[/tex]:
Isolate [tex]\(\sin(K)\)[/tex]:
[tex]\[ \sin(K) = \frac{11 \sin(18^\circ)}{7} \][/tex]
By calculating this value using a calculator:
[tex]\[ \sin(K) \approx 0.4855981340177745 \][/tex]

5. Determine Angle [tex]\( K \)[/tex]:
Use the inverse sine function (arcsin) to determine the measure of angle [tex]\( K \)[/tex]:
[tex]\[ K_1 = \sin^{-1}(0.4855981340177745) \][/tex]
Using a calculator, we find:
[tex]\[ K_1 \approx 29.05^\circ \text{ (rounded to 29 degrees)} \][/tex]

6. Ambiguous Case Consideration:
Because this is the ambiguous case (SSA condition), the measure of angle [tex]\( K \)[/tex] could also be:
[tex]\[ K_2 = 180^\circ - K_1 \][/tex]
Therefore:
[tex]\[ K_2 \approx 180^\circ - 29.05^\circ = 150.95^\circ \text{ (rounded to 151 degrees)} \][/tex]

Final Statements:

1. Triangle JKL meets the SSA (Side-Side-Angle) criteria, which means it is the ambiguous case.

2. Substitute the known values into the law of Sines:
[tex]\[ \frac{\sin(18^\circ)}{7} = \frac{\sin(K)}{11} \][/tex]

3. Cross multiply to get:
[tex]\[ 11 \sin(18^\circ) = 7 \sin(K) \][/tex]

4. Solve for the measure of angle [tex]\( K \)[/tex]:
[tex]\[ \sin(K) \approx 0.4855981340177745 \][/tex]

5. Use a calculator to determine the value:
[tex]\[ K_1 \approx 29^\circ \][/tex]

6. However, because this is the ambiguous case, the measure of angle [tex]\( K \)[/tex] could also be:
[tex]\[ K_2 \approx 151^\circ \][/tex]

So, the possible measures of angle [tex]\( K \)[/tex] are approximately [tex]\( 29^\circ \)[/tex] and [tex]\( 151^\circ \)[/tex].