Answer :

To find the 31st term of an arithmetic sequence where the first term [tex]\( a_1 = 26 \)[/tex] and the 22nd term [tex]\( a_{22} = -226 \)[/tex], we need to follow these steps:

1. Identify the formula for the nth term of an arithmetic sequence:
[tex]\[ a_n = a_1 + (n-1) \cdot d \][/tex]
where:
- [tex]\( a_n \)[/tex] is the nth term,
- [tex]\( a_1 \)[/tex] is the first term,
- [tex]\( d \)[/tex] is the common difference,
- [tex]\( n \)[/tex] is the term number.

2. Use the information given to find the common difference [tex]\( d \)[/tex]:
Since we know the 22nd term ([tex]\( a_{22} = -226 \)[/tex]):
[tex]\[ a_{22} = a_1 + 21d \][/tex]
Substituting the given values:
[tex]\[ -226 = 26 + 21d \][/tex]

Solving for [tex]\( d \)[/tex]:
[tex]\[ -226 - 26 = 21d \][/tex]
[tex]\[ -252 = 21d \][/tex]
[tex]\[ d = \frac{-252}{21} \][/tex]
[tex]\[ d = -12 \][/tex]

3. Use the common difference to find the 31st term:
Now that we have [tex]\( d = -12 \)[/tex] and we need the 31st term ([tex]\( n = 31 \)[/tex]):
[tex]\[ a_{31} = a_1 + 30d \][/tex]
Substituting the known values:
[tex]\[ a_{31} = 26 + 30(-12) \][/tex]
[tex]\[ a_{31} = 26 - 360 \][/tex]
[tex]\[ a_{31} = -334 \][/tex]

Therefore, the 31st term of the arithmetic sequence is [tex]\( -334 \)[/tex].

The correct answer is [tex]\( \boxed{-334} \)[/tex].