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What is the median value of the data?

[tex]\[
\begin{tabular}{|l|l|}
\hline
2 & $1, 2, 3, 5, 9$ \\
\hline
3 & $4, 5, 5, 8$ \\
\hline
4 & $0, 2, 5, 7$ \\
\hline
5 & $1, 5$ \\
\hline
6 & $1, 3, 8, 9$ \\
\hline
\end{tabular}
\][/tex]



Answer :

To find the median value of the data provided, follow these steps:

### Step 1: Combine All Data Elements into a Single List

First, we need to collect all elements from each row and combine them into a single list. This will be our flattened list.

Here are the elements from each row:
- Row 2: [tex]\(1, 2, 3, 5, 9\)[/tex]
- Row 3: [tex]\(4, 5, 5, 8\)[/tex]
- Row 4: [tex]\(0, 2, 5, 7\)[/tex]
- Row 5: [tex]\(1, 5\)[/tex]
- Row 6: [tex]\(1, 3, 8, 9\)[/tex]

Combining all these elements gives us:
[tex]\[ [1, 2, 3, 5, 9, 4, 5, 5, 8, 0, 2, 5, 7, 1, 5, 1, 3, 8, 9] \][/tex]

### Step 2: Sort the Combined Data List

Next, we need to sort the combined data list in ascending order:
[tex]\[ [0, 1, 1, 1, 2, 2, 3, 3, 4, 5, 5, 5, 5, 5, 7, 8, 8, 9, 9] \][/tex]

### Step 3: Calculate the Median

The median is the middle value of a sorted list.

If the number of elements [tex]\( n \)[/tex] in the list is odd, the median is the element at position [tex]\( \frac{n+1}{2} \)[/tex] (1-based index), or [tex]\( \frac{n-1}{2} \)[/tex] (0-based index).

If [tex]\( n \)[/tex] is even, the median is the average of the two middle elements.

In our sorted list, we have 19 elements:

[tex]\[ [0, 1, 1, 1, 2, 2, 3, 3, 4, 5, 5, 5, 5, 5, 7, 8, 8, 9, 9] \][/tex]

Since [tex]\( n = 19 \)[/tex], which is odd, the median will be the element at position [tex]\( \frac{19-1}{2} = 9 \)[/tex] (0-based index), which is the 10th element (1-based index).

### Step 4: Identify the Median Value

Counting to the 10th element in our sorted list, we find that the value is 5.

### Conclusion

The median value of the data is:
[tex]\[ 5 \][/tex]

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