What is the slope of a line that is parallel to [tex] y = -\frac{1}{3}x - 15 [/tex]?

A. [tex] -\frac{1}{3} [/tex]
B. [tex] \frac{1}{3} [/tex]
C. [tex] -3 [/tex]
D. [tex] 3 [/tex]



Answer :

To determine the slope of a line that is parallel to the line given by the equation [tex]\( y = -\frac{1}{3}x - 15 \)[/tex], we first need to understand the concept of parallel lines. Parallel lines have the same slope.

The given equation is in the slope-intercept form [tex]\( y = mx + b \)[/tex], where [tex]\( m \)[/tex] represents the slope and [tex]\( b \)[/tex] represents the y-intercept.

For the equation [tex]\( y = -\frac{1}{3}x - 15 \)[/tex]:

- The slope [tex]\( m \)[/tex] is [tex]\(-\frac{1}{3} \)[/tex].

Therefore, any line that is parallel to this line will have the same slope.

Thus, the slope of a line that is parallel to [tex]\( y = -\frac{1}{3}x - 15 \)[/tex] is [tex]\(-\frac{1}{3}\)[/tex].

The correct answer is [tex]\(-\frac{1}{3}\)[/tex].