Let [tex]$f(x) = x^2 + 3x - 4$[/tex] and [tex]$g(x) = x + 5$[/tex]. Find [tex][tex]$f(x) \cdot g(x)$[/tex][/tex].

A. [tex]$x^3 + 3x^2 + 16x - 20$[/tex]

B. [tex]$x^3 + 5x^2 + 14x - 20$[/tex]

C. [tex][tex]$x^3 + 8x^2 + 11x - 20$[/tex][/tex]

D. [tex]$x^3 + 9x^2 + 19x - 20$[/tex]



Answer :

To find [tex]\( f(x) \cdot g(x) \)[/tex] where [tex]\( f(x) = x^2 + 3x - 4 \)[/tex] and [tex]\( g(x) = x + 5 \)[/tex]:

1. Write the expressions for [tex]\( f(x) \)[/tex] and [tex]\( g(x) \)[/tex]:
[tex]\[ f(x) = x^2 + 3x - 4 \][/tex]
[tex]\[ g(x) = x + 5 \][/tex]

2. Setup the product [tex]\( f(x) \cdot g(x) \)[/tex]:
[tex]\[ f(x) \cdot g(x) = (x^2 + 3x - 4) \cdot (x + 5) \][/tex]

3. Distribute each term in [tex]\( f(x) \)[/tex] to every term in [tex]\( g(x) \)[/tex]:
- [tex]\( (x^2 + 3x - 4) \cdot (x + 5) \)[/tex]

[tex]\[ = x^2 \cdot (x + 5) + 3x \cdot (x + 5) - 4 \cdot (x + 5) \][/tex]

4. Multiply each term:
- [tex]\( x^2 \cdot x = x^3 \)[/tex]
- [tex]\( x^2 \cdot 5 = 5x^2 \)[/tex]
- [tex]\( 3x \cdot x = 3x^2 \)[/tex]
- [tex]\( 3x \cdot 5 = 15x \)[/tex]
- [tex]\( -4 \cdot x = -4x \)[/tex]
- [tex]\( -4 \cdot 5 = -20 \)[/tex]

Combine the results:
[tex]\[ x^3 + 5x^2 + 3x^2 + 15x - 4x - 20 \][/tex]

5. Combine like terms:
- [tex]\( 5x^2 + 3x^2 = 8x^2 \)[/tex]
- [tex]\( 15x - 4x = 11x \)[/tex]

Simplify:
[tex]\[ x^3 + 8x^2 + 11x - 20 \][/tex]

Thus, the product [tex]\( f(x) \cdot g(x) \)[/tex] is:
[tex]\[ x^3 + 8x^2 + 11x - 20 \][/tex]

The correct option is:
[tex]\[ \boxed{x^3 + 8x^2 + 11x - 20} \][/tex]