Question 1 (Multiple Choice Worth 3 points)

In an experiment, calcium carbonate reacted with different volumes of hydrochloric acid in water. One of the products formed during the experiment was carbon dioxide. A partial record of the experiment is shown.

Experimental Record

[tex]\[
\begin{tabular}{|l|l|l|l|c|}
\hline
Flask & \multicolumn{1}{|c|}{\begin{tabular}{c}
Mass of \\ Calcium Carbonate
\end{tabular}} & \begin{tabular}{c}
Volume of \\ HCl
\end{tabular} & \begin{tabular}{c}
Volume of \\ Water
\end{tabular} & \multicolumn{1}{|c|}{ Time } \\
\hline
1 & 4.0 g & 25 mL & 0 mL & 11.2 seconds \\
\hline
2 & 4.0 g & 20 mL & 5 mL & \\
\hline
3 & 4.0 g & 15 mL & 10 mL & \\
\hline
4 & 4.0 g & 10 mL & 15 mL & \\
\hline
\end{tabular}
\][/tex]

Based on factors that affect the rates of chemical reactions, which of the following would describe the trend expected in the table?

A. Time increases as the volume of hydrochloric acid decreases

B. Time increases as the volume of hydrochloric acid remains the same

C. Time decreases as the mass of calcium carbonate decreases

D. Time decreases as the mass of calcium carbonate remains the same



Answer :

The rates of chemical reactions can be influenced by several factors such as the concentration of reactants, temperature, surface area of reactants, catalysts, and the presence of mixing or agitation. In this particular scenario, we are dealing with the concentration of hydrochloric acid (HCl) as a key factor affecting the reaction rate.

From the given experimental record, we can observe the following data points:

- Flask 1: 25 mL of HCl, 0 mL of Water, Time = 11.2 seconds
- Flask 2: 20 mL of HCl, 5 mL of Water, Time = Unknown
- Flask 3: 15 mL of HCl, 10 mL of Water, Time = Unknown
- Flask 4: 10 mL of HCl, 15 mL of Water, Time = Unknown

As the volume of HCl decreases from Flask 1 to Flask 4, the concentration of HCl in the solution also decreases. Since HCl is a reactant in the chemical reaction with calcium carbonate, a lower concentration of HCl means there are fewer HCl molecules available to collide with calcium carbonate particles. As a result:

- The reaction rate will decrease.
- The time taken for the reaction to complete will increase.

Therefore, the expected trend in the table is that the time taken for the reaction increases as the volume of hydrochloric acid decreases.

The correct answer is:
Time increases as the volume of hydrochloric acid decreases.