Answer :
Let's solve the given problems step-by-step.
### i. तीमध्ये पारोको पहिचान गन्नुहोस् । (Identify mercury from the above table.)
Given data:
\begin{tabular}{|c|c|}
\hline \begin{tabular}{c}
तरल \\
(Liquid)
\end{tabular} & \begin{tabular}{c}
विस्थापित पिण्ड \\
(Displaced mass in kg )
\end{tabular} \\
\hline A & 1 \\
\hline B & 13.6 \\
\hline C & 1.5 \\
\hline
\end{tabular}
Among these liquids, we know that mercury (पारो) is a very dense liquid. Therefore, it will displace the least volume when the same amount of solid is immersed in it. Consequently, the displaced mass will be the highest.
By observing the given displaced mass, liquid B has the highest displaced mass, which is 13.6 kg.
Thus, पारो (mercury) is:
पारो = B
### ii. यदि हरेक तरलको आयतन समान छ ? समान किसियको भाडामा राखिएको छ. भने कुन तरलको विस्थापित आयतन सवैभन्दा वडी हुन्छ : आर्किमिडिजको सिद्धान्तको अधारमा कारण दिनुहोस् । (If each liquid has same volume in similar container, displaced mass of which liquid has more volume? Write the reason on the basis of Archimedes' principle.)
Archimedes' principle states that the weight of the liquid displaced by an object is equal to the weight of the object. In other words, the buoyant force is equal to the weight of the displaced liquid.
Given data:
\begin{tabular}{|c|c|}
\hline \begin{tabular}{c}
तरल \\
(Liquid)
\end{tabular} & \begin{tabular}{c}
विस्थापित पिण्ड \\
(Displaced mass in kg )
\end{tabular} \\
\hline A & 1 \\
\hline B & 13.6 \\
\hline C & 1.5 \\
\hline
\end{tabular}
We are given that the volume of each of these liquids is the same. To determine which liquid will have the maximum displaced volume, we need to consider the liquid with the lowest density because a liquid with a lower density will displace a greater volume when the same mass of an object is immersed in it.
By the given displaced mass, liquid A has the smallest displaced mass, which is 1 kg. This implies liquid A has the lowest density among the three.
Therefore, the liquid with the maximum displaced volume for the same volume of the solid object is:
विस्थापित आयतन = A
### Summary:
i. पारो (mercury) is identified as liquid B.
ii. Liquid A will have the maximum displaced volume, as it has the lowest density according to Archimedes' principle.
### i. तीमध्ये पारोको पहिचान गन्नुहोस् । (Identify mercury from the above table.)
Given data:
\begin{tabular}{|c|c|}
\hline \begin{tabular}{c}
तरल \\
(Liquid)
\end{tabular} & \begin{tabular}{c}
विस्थापित पिण्ड \\
(Displaced mass in kg )
\end{tabular} \\
\hline A & 1 \\
\hline B & 13.6 \\
\hline C & 1.5 \\
\hline
\end{tabular}
Among these liquids, we know that mercury (पारो) is a very dense liquid. Therefore, it will displace the least volume when the same amount of solid is immersed in it. Consequently, the displaced mass will be the highest.
By observing the given displaced mass, liquid B has the highest displaced mass, which is 13.6 kg.
Thus, पारो (mercury) is:
पारो = B
### ii. यदि हरेक तरलको आयतन समान छ ? समान किसियको भाडामा राखिएको छ. भने कुन तरलको विस्थापित आयतन सवैभन्दा वडी हुन्छ : आर्किमिडिजको सिद्धान्तको अधारमा कारण दिनुहोस् । (If each liquid has same volume in similar container, displaced mass of which liquid has more volume? Write the reason on the basis of Archimedes' principle.)
Archimedes' principle states that the weight of the liquid displaced by an object is equal to the weight of the object. In other words, the buoyant force is equal to the weight of the displaced liquid.
Given data:
\begin{tabular}{|c|c|}
\hline \begin{tabular}{c}
तरल \\
(Liquid)
\end{tabular} & \begin{tabular}{c}
विस्थापित पिण्ड \\
(Displaced mass in kg )
\end{tabular} \\
\hline A & 1 \\
\hline B & 13.6 \\
\hline C & 1.5 \\
\hline
\end{tabular}
We are given that the volume of each of these liquids is the same. To determine which liquid will have the maximum displaced volume, we need to consider the liquid with the lowest density because a liquid with a lower density will displace a greater volume when the same mass of an object is immersed in it.
By the given displaced mass, liquid A has the smallest displaced mass, which is 1 kg. This implies liquid A has the lowest density among the three.
Therefore, the liquid with the maximum displaced volume for the same volume of the solid object is:
विस्थापित आयतन = A
### Summary:
i. पारो (mercury) is identified as liquid B.
ii. Liquid A will have the maximum displaced volume, as it has the lowest density according to Archimedes' principle.