At a track meet, there are 8 runners competing in the 400-meter race. How many ways can the runners finish the race? (Assume all of the runners finish, and there are no ties.)

Select the correct answer.

A. [tex]$3! = 336$[/tex]

B. [tex]$8! = 40,320$[/tex]

C. [tex]$3! = 6$[/tex]

D. [tex]$8! = 5,040$[/tex]



Answer :

To determine the number of ways 8 runners can finish the race, we need to consider all the possible permutations of the 8 runners. When we talk about permutations, we are referring to the different ways in which a set of items can be arranged.

Since we have 8 runners, we need to find the number of permutations of 8 distinct items. This is mathematically represented as [tex]\(8!\)[/tex] (8 factorial). The factorial of a number [tex]\(n\)[/tex] is the product of all positive integers less than or equal to [tex]\(n\)[/tex]. So, to find [tex]\(8!\)[/tex], we multiply all the integers from 1 to 8 together:

[tex]\[ 8! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 \][/tex]

Calculating this step by step:

1. [tex]\(8 \times 7 = 56\)[/tex]
2. [tex]\(56 \times 6 = 336\)[/tex]
3. [tex]\(336 \times 5 = 1680\)[/tex]
4. [tex]\(1680 \times 4 = 6720\)[/tex]
5. [tex]\(6720 \times 3 = 20160\)[/tex]
6. [tex]\(20160 \times 2 = 40320\)[/tex]
7. [tex]\(40320 \times 1 = 40320\)[/tex]

Therefore, the number of ways the 8 runners can finish the race is:

[tex]\[ 8! = 40320 \][/tex]

Given the choices available, the correct answer is [tex]\(8! = 40,320\)[/tex].