An elevator, which takes off from the ground floor of a
4-storey building, goes up to the 4th floor at a speed of
one-third of its speed on the previous floor on each floor.
Then, on each floor, it travels at twice the speed of the
previous floor and descends to the ground floor.
Since the descending and ascending times of the elevator
are equal, what is the ratio of the speed of ascending from
the ground floor to the 1st floor to the speed of descending
from the 4th floor to the 3rd floor?
(The distance between floors is equal.)



Answer :

Answer:

Thus, the ratio of the speed of ascending from the ground floor to the 1st floor to the speed of descending from the 4th floor to the 3rd floor is

64/3 .

Step-by-step explanation:

Solving for the Ratio v/u:

40×8u=15v

320u=15v

/u=320/15=64/3