A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.)

Enter the units of the student's answer.

[tex]\[ \frac{(1.32 \text{ mol})\left(\frac{1 \text{ mL}}{10^{-3} \text{ L}}\right)}{\left(7.0 \frac{\text{ mol }}{\text{ L }}\right)} = ? \][/tex]



Answer :

Let's break down the given equation:

[tex]\[ \frac{(1.32 \, \text{mol}) \left( \frac{1 \, \text{mL}}{10^{-3} \, \text{L}} \right)}{\left( 7.0 \, \frac{\text{mol}}{\text{L}} \right)} = ? \][/tex]
Recall, the problem gives us:
- [tex]\(1.32 \, \text{mol}\)[/tex] of the substance.
- A conversion factor [tex]\(\frac{1 \, \text{mL}}{10^{-3} \, \text{L}}\)[/tex] which converts milliliters to liters.
- A concentration of [tex]\(7.0 \, \frac{\text{mol}}{\text{L}}\)[/tex].

Let's follow these steps:

1. Convert moles to volume in liters:
We start by finding the volume in liters that contains 1.32 moles at a concentration of [tex]\(7.0 \, \text{mol/L}\)[/tex]:
[tex]\[ \text{Volume in L} = \frac{\text{Moles}}{\text{Concentration}} = \frac{1.32 \, \text{mol}}{7.0 \, \text{mol/L}} \][/tex]
This calculation provides the volume in liters as:
[tex]\[ \text{Volume in L} = 0.18857142857142858 \, \text{L} \][/tex]

2. Convert liters to milliliters:
Since [tex]\(1 \, \text{L} = 1000 \, \text{mL}\)[/tex] (or equivalently [tex]\(1 \, \text{mL} = 10^{-3} \, \text{L}\)[/tex]), we multiply the volume in liters by 1000 to convert to milliliters:
[tex]\[ \text{Volume in mL} = 0.18857142857142858 \, \text{L} \times 1000 \, \frac{\text{mL}}{\text{L}} = 188.57142857142858 \, \text{mL} \][/tex]

3. Units of the answer:
The student's answer should be expressed in milliliters (mL) because we converted the volume from liters to milliliters during our calculations.

Therefore, the units of the student's answer are:
[tex]\[ \boxed{\text{mL}} \][/tex]

The detailed steps demonstrate the complete process of reaching the final units in milliliters (mL).