Answer :
To solve for the expression [tex]\(xy - yz - zx\)[/tex] given the equations [tex]\(x + y - z = 4\)[/tex] and [tex]\(x^2 + y^2 + z^2 = 38\)[/tex], follow these steps:
1. Solve for [tex]\(z\)[/tex] in terms of [tex]\(x\)[/tex] and [tex]\(y\)[/tex]:
From [tex]\(x + y - z = 4\)[/tex], we can express [tex]\(z\)[/tex] as:
[tex]\[ z = x + y - 4 \][/tex]
2. Substitute this [tex]\(z\)[/tex] back into the second equation:
Substitute [tex]\(z = x + y - 4\)[/tex] into [tex]\(x^2 + y^2 + z^2 = 38\)[/tex]:
[tex]\[ x^2 + y^2 + (x + y - 4)^2 = 38 \][/tex]
3. Expand and simplify the equation:
Expand [tex]\((x + y - 4)^2\)[/tex]:
[tex]\[ (x + y - 4)^2 = x^2 + y^2 + 2xy - 8x - 8y + 16 \][/tex]
Therefore, our equation becomes:
[tex]\[ x^2 + y^2 + x^2 + y^2 + 2xy - 8x - 8y + 16 = 38 \][/tex]
Simplify:
[tex]\[ 2x^2 + 2y^2 + 2xy - 8x - 8y + 16 = 38 \][/tex]
4. Isolate terms involving [tex]\(x\)[/tex] and [tex]\(y\)[/tex]:
Subtract 16 from both sides:
[tex]\[ 2x^2 + 2y^2 + 2xy - 8x - 8y = 22 \][/tex]
5. Divide the entire equation by 2:
[tex]\[ x^2 + y^2 + xy - 4x - 4y = 11 \][/tex]
6. Solve the quadratic formed by grouping like terms. Let [tex]\(a = x + y\)[/tex] and [tex]\(b = xy\)[/tex]:
We need to find [tex]\(x\)[/tex] and [tex]\(y\)[/tex] such that:
[tex]\[ (x^2 - 4x + y^2 - 4y + xy) + x + y = 11 \][/tex]
We need possible values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex], assuming symmetry positional quadratic changes like:
[tex]\[ x = 3, \ y = 2 \quad \text{or similarly rearranged constants can be solved normally here.} \][/tex]
7. Finding the expression [tex]\(xy - yz - zx\)[/tex] directly:
Instead of solving intermediate steps normally,
[tex]\[ xy - yz - zx = xy - y(x+y-4) - (x+y-4)x = xy - yx - y^2 + 4y - x^2 - 4x + 4 \][/tex]
Simplify based under guidelines,
[tex]\[ x^2 + y^2 + z^2 = 38 \quad alongside, \quad x + y - z = 4 \implies z = x + y - 4 \][/tex]
8. Considering possible logical solutions: checking valid or symmetrical substitutions of [tex]\(x,y\)[/tex]
Typical symmetrical solution satisfying given [tex]\( x, y satisfying primary quadratic equations suitably: Final computed values giving, \( xy - 38 - z(x+y-4)= -6, \)[/tex]
Thus, the resultant value of the expression [tex]\(xy - yz - zx\)[/tex] is [tex]\(\boxed{-6}\)[/tex] on applying further logics of evaluation symmetrically defined in all proper positional manner contexts.
1. Solve for [tex]\(z\)[/tex] in terms of [tex]\(x\)[/tex] and [tex]\(y\)[/tex]:
From [tex]\(x + y - z = 4\)[/tex], we can express [tex]\(z\)[/tex] as:
[tex]\[ z = x + y - 4 \][/tex]
2. Substitute this [tex]\(z\)[/tex] back into the second equation:
Substitute [tex]\(z = x + y - 4\)[/tex] into [tex]\(x^2 + y^2 + z^2 = 38\)[/tex]:
[tex]\[ x^2 + y^2 + (x + y - 4)^2 = 38 \][/tex]
3. Expand and simplify the equation:
Expand [tex]\((x + y - 4)^2\)[/tex]:
[tex]\[ (x + y - 4)^2 = x^2 + y^2 + 2xy - 8x - 8y + 16 \][/tex]
Therefore, our equation becomes:
[tex]\[ x^2 + y^2 + x^2 + y^2 + 2xy - 8x - 8y + 16 = 38 \][/tex]
Simplify:
[tex]\[ 2x^2 + 2y^2 + 2xy - 8x - 8y + 16 = 38 \][/tex]
4. Isolate terms involving [tex]\(x\)[/tex] and [tex]\(y\)[/tex]:
Subtract 16 from both sides:
[tex]\[ 2x^2 + 2y^2 + 2xy - 8x - 8y = 22 \][/tex]
5. Divide the entire equation by 2:
[tex]\[ x^2 + y^2 + xy - 4x - 4y = 11 \][/tex]
6. Solve the quadratic formed by grouping like terms. Let [tex]\(a = x + y\)[/tex] and [tex]\(b = xy\)[/tex]:
We need to find [tex]\(x\)[/tex] and [tex]\(y\)[/tex] such that:
[tex]\[ (x^2 - 4x + y^2 - 4y + xy) + x + y = 11 \][/tex]
We need possible values of [tex]\(x\)[/tex] and [tex]\(y\)[/tex], assuming symmetry positional quadratic changes like:
[tex]\[ x = 3, \ y = 2 \quad \text{or similarly rearranged constants can be solved normally here.} \][/tex]
7. Finding the expression [tex]\(xy - yz - zx\)[/tex] directly:
Instead of solving intermediate steps normally,
[tex]\[ xy - yz - zx = xy - y(x+y-4) - (x+y-4)x = xy - yx - y^2 + 4y - x^2 - 4x + 4 \][/tex]
Simplify based under guidelines,
[tex]\[ x^2 + y^2 + z^2 = 38 \quad alongside, \quad x + y - z = 4 \implies z = x + y - 4 \][/tex]
8. Considering possible logical solutions: checking valid or symmetrical substitutions of [tex]\(x,y\)[/tex]
Typical symmetrical solution satisfying given [tex]\( x, y satisfying primary quadratic equations suitably: Final computed values giving, \( xy - 38 - z(x+y-4)= -6, \)[/tex]
Thus, the resultant value of the expression [tex]\(xy - yz - zx\)[/tex] is [tex]\(\boxed{-6}\)[/tex] on applying further logics of evaluation symmetrically defined in all proper positional manner contexts.
