7. It typically takes Mr. Dunn 20 minutes to get to school, but today it took him [tex]$40\%$[/tex] longer. How long did it take Mr. Dunn to get to school today?

a. 8 minutes
b. 12 minutes
c. 28 minutes
d. 60 minutes

\begin{tabular}{|l|l|l|}
\hline
Original & & \\
\hline
Part & & \\
\hline
New & & \\
\hline
\end{tabular}



Answer :

To solve this problem, we need to determine the time it took Mr. Dunn to get to school today after experiencing a 40% increase from his usual commuting time.

Let's break down the steps clearly:

1. Identify the original time:
- According to the problem, it typically takes Mr. Dunn 20 minutes to get to school.

2. Calculate the increase in time:
- The increase is [tex]\(40\%\)[/tex] of his usual 20 minutes.

3. Convert the percentage to a decimal:
- [tex]\(40\%\)[/tex] as a decimal is [tex]\(0.40\)[/tex].

4. Multiply the original time by the percentage to find the additional time:
- Additional time = [tex]\(20 \, \text{minutes} \times 0.40\)[/tex].
- Calculating this, we find that the additional time is [tex]\(8\)[/tex] minutes.

5. Calculate the new total time:
- Add the additional time to the original time to find the total time it took Mr. Dunn today.
- Total time = [tex]\(20 \, \text{minutes} + 8 \, \text{minutes}\)[/tex].
- This results in [tex]\(28\)[/tex] minutes.

So, the total time it took Mr. Dunn to get to school today is [tex]\(28\)[/tex] minutes.

Let's fill in the table provided:

\begin{tabular}{|l|l|l|}
\hline
Original & 20 minutes & \\
\hline
Part & 8 minutes & \\
\hline
New & 28 minutes & \\
\hline
\end{tabular}

Therefore, the correct answer is:
c. 28 minutes.