The frequency table below shows the ages of the students in an astronomy class.
Complete the Relative Frequency column of the table. Enter answers as an unsimplified fraction.

Provide your answer below:

\begin{tabular}{|c|c|c|}
\hline
Age & Frequency & \begin{tabular}{c}
Relative \\
Frequency
\end{tabular} \\
\hline
17 & 6 & [tex]$\square$[/tex] \\
\hline
18 & 5 & [tex]$\square$[/tex] \\
\hline
19 & 12 & [tex]$\square$[/tex] \\
\hline
20 & 15 & [tex]$\square$[/tex] \\
\hline
21 & 8 & [tex]$\square$[/tex] \\
\hline
22 & 4 & [tex]$\square$[/tex] \\
\hline
\end{tabular}



Answer :

To complete the 'Relative Frequency' column, we need to compute the relative frequency for each age group. The relative frequency is determined by dividing the frequency of each age group by the total frequency of all age groups.

The total frequency is calculated by summing up the frequencies of all the age groups:

[tex]\[6 + 5 + 12 + 15 + 8 + 4 = 50\][/tex]

Now, let's determine the relative frequency for each age group by dividing each frequency by the total frequency of 50:

1. For age 17: [tex]\(\frac{6}{50}\)[/tex]
2. For age 18: [tex]\(\frac{5}{50}\)[/tex]
3. For age 19: [tex]\(\frac{12}{50}\)[/tex]
4. For age 20: [tex]\(\frac{15}{50}\)[/tex]
5. For age 21: [tex]\(\frac{8}{50}\)[/tex]
6. For age 22: [tex]\(\frac{4}{50}\)[/tex]

Therefore, the completed table with the relative frequencies is:

\begin{tabular}{|c|c|c|}
\hline
Age & Frequency & \begin{tabular}{c}
Relative \\
Frequency
\end{tabular} \\
\hline
17 & 6 & [tex]\(\frac{6}{50}\)[/tex] \\
\hline
18 & 5 & [tex]\(\frac{5}{50}\)[/tex] \\
\hline
19 & 12 & [tex]\(\frac{12}{50}\)[/tex] \\
\hline
20 & 15 & [tex]\(\frac{15}{50}\)[/tex] \\
\hline
21 & 8 & [tex]\(\frac{8}{50}\)[/tex] \\
\hline
22 & 4 & [tex]\(\frac{4}{50}\)[/tex] \\
\hline
\end{tabular}