To determine which event has the highest probability, we need to calculate the probabilities associated with each of the specified events.
1. Probability that the bus is from route C and is delayed:
- The number of buses from route C that are delayed: 6
- Total number of buses: 110
- Probability: [tex]\(\frac{6}{110} \approx 0.0545\)[/tex]
2. Probability that the bus is from route B and is delayed:
- The number of buses from route B that are delayed: 8
- Total number of buses: 110
- Probability: [tex]\(\frac{8}{110} \approx 0.0727\)[/tex]
3. Probability that the bus is from route A and is on time:
- The number of buses from route A that are on time: 28
- Total number of buses: 110
- Probability: [tex]\(\frac{28}{110} \approx 0.2545\)[/tex]
4. Probability that the bus is from route C and is on time:
- The number of buses from route C that are on time: 24
- Total number of buses: 110
- Probability: [tex]\(\frac{24}{110} \approx 0.2182\)[/tex]
By comparing these probabilities, we observe that:
- The probability the bus is from route C and is delayed is approximately 0.0545.
- The probability the bus is from route B and is delayed is approximately 0.0727.
- The probability the bus is from route A and is on time is approximately 0.2545.
- The probability the bus is from route C and is on time is approximately 0.2182.
Among these probabilities, the highest one is 0.2545, which corresponds to the event that the bus is from route A and is on time.
Therefore, the event with the highest probability is:
C. The bus is from route [tex]\(A\)[/tex] and is on time.
