Answer:
[tex]x\leq 15[/tex]
Step-by-step explanation:
To solve an inequality algebraically, first you must distribute and make sure that all terms are in proper form without any addition expressions. From there you must isolate the variable(x) from the constants(numbers) to solve for what x specifically is.
Solving:
[tex]5(x - 2) \leq 3x + 20 ~( \text{Distribute the 5}) \\\\5x - 10 \leq 3x + 20 ~( \text{Subtract 3x from both sides})\\\\5x - 10 - 3x \leq 3x + 20 - 3x ~( \text{Evaluate})\\\\2x - 10 \leq 20 ~( \text{Add 10 to both sides})\\\\2x - 10 + 10 \leq 20 + 10 ~( \text{Evaluate})\\\\2x \leq 30~( \text{Divide both sides by 2 to get just x}) \\\\\frac{2x}{2} \leq \frac{30}{2} ~( \text{Evaluate})\\\\\boxed{x \leq 15}[/tex]
